The circuit of Fig. P7.15 is called a current mirror because with R1 5 R2 it gives, in the limit av → `, iO 5 iI . (a) Using KVL, KCL, and the op amp relationship vOA 5 avvE, show that the circuit...

The circuit of Fig. P7.15 is called a current mirror because with R1 5 R2 it gives, in the limit av → `, iO 5 iI . (a) Using KVL, KCL, and the op amp relationship vOA 5 avvE, show that the circuit gives iO 5 AiI 2 vOyRo, where A and Ro are suitable functions of av, R1, and R2. Clearly, A is the closed-loop gain, and Ro is the circuit’s output resistance as seen by the load. (b) Calculate A and Ro if R1 5 2R2 5 20 kV and av 5 `. Repeat, but for av 5 103 V/V, and comment.