The calcul of this weight CcFaFy23(KI/r)2Pa =FaAExpressions for beam:MR = F,S, in which S =-Expressions for tension member:Pt = A,F , in which F = 0.6FyP; = A,Ft , in which F = 0.5FuP =...

The calcul of this weight
Appendix<br>Expressions for axially loaded compression member:<br>KI<br>For-< C. =<br>2T²E<br>[1 – (Kl/r)²/(2C? )]Fy<br>F, =<br>5 3(Kl/r) _ (Kl/r)³<br>8Cc<br>Fy<br>|21²E<br>1212E<br>KI<br>For-> Cc<br>Fa<br>Fy<br>23(KI/r)2<br>Pa =<br>FaA<br>Expressions for beam:<br>MR = F,S, in which S =-<br>Expressions for tension member:<br>Pt = A,F , in which F = 0.6Fy<br>P; = A,Ft , in which F = 0.5Fu<br>P = A.Ft , in which Ae = U An, F = 0.5Fu<br>P = A,F, + A,F; , in which Fy = 0.30Fµ , F; = 0.50Fu<br>P = nr,, in which r, = ApFv, ry = d t F,<br>TABLE 2-1 Values for Reduction Coefficient, U<br>U = 0.90<br>W, M, S shapes or their tees.<br>Connection is to the flanges.<br>Minimum of three bolts per line in the direction of<br>Case I<br>stress.<br>(min.)<br>(min.)<br>U = 0,85<br>All shapes and built-up cross sections not meeting<br>the requirements of case I. Minimum of three bolts<br>per line in the direction of stress.<br>Case II<br>U = 0.75<br>All members whose connections have only two bolts<br>per line in the direction of stress.<br>Case III<br>Units:<br>ksi : kips per square inch<br>kips: kilo pounds<br>lb/ft: pounds per foot<br>kips/ft: kilo pounds per foot<br>

Extracted text: Appendix Expressions for axially loaded compression member: KI For-< c.="2T²E" [1="" –="" (kl/r)²/(2c?="" )]fy="" f,="5" 3(kl/r)="" _="" (kl/r)³="" 8cc="" fy="" |21²e="" 1212e="" ki="" for-=""> Cc Fa Fy 23(KI/r)2 Pa = FaA Expressions for beam: MR = F,S, in which S =- Expressions for tension member: Pt = A,F , in which F = 0.6Fy P; = A,Ft , in which F = 0.5Fu P = A.Ft , in which Ae = U An, F = 0.5Fu P = A,F, + A,F; , in which Fy = 0.30Fµ , F; = 0.50Fu P = nr,, in which r, = ApFv, ry = d t F, TABLE 2-1 Values for Reduction Coefficient, U U = 0.90 W, M, S shapes or their tees. Connection is to the flanges. Minimum of three bolts per line in the direction of Case I stress. (min.) (min.) U = 0,85 All shapes and built-up cross sections not meeting the requirements of case I. Minimum of three bolts per line in the direction of stress. Case II U = 0.75 All members whose connections have only two bolts per line in the direction of stress. Case III Units: ksi : kips per square inch kips: kilo pounds lb/ft: pounds per foot kips/ft: kilo pounds per foot
1. Calculate the weight (in pounds) of a 1-ft length of a steel built-up member having a cross<br>section as shown. (unit weight of steel: 490 lb/ft³ ) (1ft =12 in. )<br>91 x 6a-<br>W16 X 67<br>wL4X 3 x<br>L3 X 3 x<br>

Extracted text: 1. Calculate the weight (in pounds) of a 1-ft length of a steel built-up member having a cross section as shown. (unit weight of steel: 490 lb/ft³ ) (1ft =12 in. ) 91 x 6a- W16 X 67 wL4X 3 x L3 X 3 x
Jun 11, 2022
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