The armature shaft of a 50 kW, 580 rpm electric motor, mounted on two bearings A and B, is shown in Fig. The total magnetic pull on the armature is 5 kN and it can be assumed to be uniformly...


The armature shaft of a 50 kW, 580 rpm<br>electric motor, mounted on two bearings A and<br>B, is shown in Fig. The total magnetic pull<br>on the armature is 5 kN and it can be assumed to<br>be uniformly distributed over a length of 400 mm<br>midway between the bearings. The shaft is made of<br>steel with an ultimate tensile strength of 770 N/mm?<br>and yield strength of 580 N/mm?. Determine the<br>shaft diameter using the ASME code if,<br>k = 1.5 and k, = 1.0<br>Assume that the pulley is keyed to the shaft.<br>150<br>400<br>10 N/mm<br>150<br>300<br>1000 N<br>3000 N<br>

Extracted text: The armature shaft of a 50 kW, 580 rpm electric motor, mounted on two bearings A and B, is shown in Fig. The total magnetic pull on the armature is 5 kN and it can be assumed to be uniformly distributed over a length of 400 mm midway between the bearings. The shaft is made of steel with an ultimate tensile strength of 770 N/mm? and yield strength of 580 N/mm?. Determine the shaft diameter using the ASME code if, k = 1.5 and k, = 1.0 Assume that the pulley is keyed to the shaft. 150 400 10 N/mm 150 300 1000 N 3000 N

Jun 11, 2022
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