The answer above is NOT correct. Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error...


The answer above is NOT correct.<br>Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl.<br>We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4.<br>The plaintext given by<br>11100010 — ХоXјX2XҙX4XsX6X7<br>when encrypted by the LFSR produced the ciphertext<br>11010110 — Уo У1 У2 Уз Уз У5 У6 Ут.<br>What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent p3 = 0, p2 = 1, p1 = 0, po = 1).<br>0010<br>

Extracted text: The answer above is NOT correct. Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4. The plaintext given by 11100010 — ХоXјX2XҙX4XsX6X7 when encrypted by the LFSR produced the ciphertext 11010110 — Уo У1 У2 Уз Уз У5 У6 Ут. What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent p3 = 0, p2 = 1, p1 = 0, po = 1). 0010

Jun 07, 2022
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