The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.887 g and a standard deviation of 0.319 g. The company that produces these cigarettes claims that it...

Extracted text: The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.887 g and a standard deviation of 0.319 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 36 cigarettes with a mean nicotine amount of 0.791 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 36 cigarettes with a mean of 0.791 g or less. P(M < 0.791="" g)="Enter" your="" answer="" as="" a="" number="" accurate="" to="" 4="" decimal="" places.="" note:="" answers="" obtained="" using="" exact="" z-="" scores="" or="" z-scores="" rounded="" to="" 3="" decimal="" places="" are="" accepted.="" based="" on="" the="" result="" above,="" is="" it="" valid="" to="" claim="" that="" the="" amoutn="" of="" nicotine="" is="" lower?="" o="" no.="" the="" probability="" of="" obtaining="" this="" data="" is="" high="" enough="" to="" have="" been="" a="" chance="" occurrence.="" o="" yes.="" the="" probability="" of="" this="" data="" is="" unlikely="" to="" have="" occurred="" by="" chance="">