Task: Find the true value of p. ( Please don't give me the answer to the problem, I only need the true value of p.) Problem: A random sample of 319 male veterans who suffered from posttraumatic stress...

Task: Find the true value of p. (Please don't give me the answer to the problem, I only need the true value of p.)

Problem: A random sample of 319 male veterans who suffered from posttraumatic stress disorder (PTSD) was selected to participate in the study reported in the Journal of Applied Psychology. Of these 319 veterans, 43 were unemployed; construct a 95% confidence interval for the percentage of all such veterans who suffer from PDTD who are unemployed.

Note: First picture is the answer to the problem. Only left to find is the true value of p.

Extracted text: Step-by-step explanation x= 43 n= 319 point estimate, p=x/n = 43/319 hypothesized population proprotion , p= 0.1348 hypothesis HO: p =0.1348 Ha: p# 0.1348 z citical value at 95% confidence is 1.96 confidence interval is given by p +/- zc'sqrt(p*(1-Đ)/n) 0.1348 +/- 1.96*sqrt(0.1348 *(1-0.1348 )/319) 0.1348 +/- 0.03748 0.0973 ,0.17228 95% confidence interval for the percentage of all such veterans who suffered from PTSD who are unemployed is between 9.73% and 17.23%