Table 1 Approximate Cost for an n x n Matrix A with Large n Algorithm Cost in Flops Gauss-Jordan elimination (forward phase) Gauss-Jordan elimination (backward phase) n? LU-decomposition of A Forward...


Table 1<br>Approximate Cost for an n x n Matrix A with Large n<br>Algorithm<br>Cost in Flops<br>Gauss-Jordan elimination (forward phase)<br>Gauss-Jordan elimination (backward phase) n?<br>LU-decomposition of A<br>Forward substitution to solve Ly = b<br>Backward substitution to solve Ux = y<br>A-' by reducing [A |I] to [! | A-']<br>* 2n3<br>Compute A-'b<br>* 2n<br>3<br>

Extracted text: Table 1 Approximate Cost for an n x n Matrix A with Large n Algorithm Cost in Flops Gauss-Jordan elimination (forward phase) Gauss-Jordan elimination (backward phase) n? LU-decomposition of A Forward substitution to solve Ly = b Backward substitution to solve Ux = y A-' by reducing [A |I] to [! | A-'] * 2n3 Compute A-'b * 2n 3
4. The IBM Sequoia computer can operate at speeds in excess<br>of 16 petaflops per second (1 petaflop = 1015 flops). Use Ta-<br>ble 1 to estimate the time required to perform the following<br>operations on an invertible 100,000 × 100,000 matrix A.<br>(a) Execute the forward phase of Gauss-Jordan elimination.<br>(b) Execute the backward phase of Gauss-Jordan elimina-<br>tion.<br>(c) LU-decomposition of A.<br>(d) Find A-l by reducing [A | I] to [I | A¬'].<br>

Extracted text: 4. The IBM Sequoia computer can operate at speeds in excess of 16 petaflops per second (1 petaflop = 1015 flops). Use Ta- ble 1 to estimate the time required to perform the following operations on an invertible 100,000 × 100,000 matrix A. (a) Execute the forward phase of Gauss-Jordan elimination. (b) Execute the backward phase of Gauss-Jordan elimina- tion. (c) LU-decomposition of A. (d) Find A-l by reducing [A | I] to [I | A¬'].

Jun 05, 2022
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