Suppose we were not told that 20% of M&Ms are blue by the company, but instead want to estimate this population proportion through a confidence interval. Taking a sample of 100 M&Ms, 19% of them were...

Suppose we were not told that 20% of M&Ms are blue by the company, but instead want to estimate this population proportion through a confidence interval. Taking a sample of 100 M&Ms, 19% of them were blue. Using a 99% confidence level, what is the
margin of error
on the estimate of 19%? Round to three decimal places.