Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean p = 194 days and standard deviation o = 16 days. Complete parts (a) through (f) below. The...


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Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean p = 194 days and standard deviation o = 16 days. Complete parts (a) through (f) below.<br>The probability that a randomly selected pregnancy lasts less than 188 days is approximately 0.3538. (Round to four decimal places as needed.)<br>Interpret this probability. Select the correct choice below and fill in the answer box within your choice.<br>(Round to the nearest integer as needed.)<br>A. If 100 pregnant individuals were selected independently from this population, we would expect<br>pregnancies to last exactly 188 days.<br>O B. If 100 pregnant individuals were selected independently from this population, we would expect 35 pregnancies to last less than 188 days.<br>C. If 100 pregnant individuals were selected independently from this population, we would expect<br>pregnancies to last more than 188 days.<br>(b) Suppose a random sample of 18 pregnancies is obtained. Describe the sampling distribution of the sample mean length of pregnancies.<br>The sampling distribution of x is<br>= 194 and o; = 3.7712.<br>normal<br>with<br>(Round to four decimal places as needed.)<br>(c) What is the probability that a random sample of 18 pregnancies has a mean gestation period of 188 days or less?<br>The probability that the mean of a random sample of 18 pregnancies is less than 188 days is approximately .0558 .<br>(Round to four decimal places as needed.)<br>Interpret this probability. Select the correct choice below and fill in the answer box within your choice.<br>(Round to the nearest integer as needed.)<br>A. If 100 independent random samples of size n= 18 pregnancies were obtained from this population, we would expect<br>sample(s) to have a sample mean of 188 days or less.<br>O B.<br>If 100 incdenendent random camples of cize n – 12 nreanancies were ohtained from thie nonulation<br>Lwe would evp ect<br>camplelel to have a sample mean of 188 dave or more<br>

Extracted text: Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean p = 194 days and standard deviation o = 16 days. Complete parts (a) through (f) below. The probability that a randomly selected pregnancy lasts less than 188 days is approximately 0.3538. (Round to four decimal places as needed.) Interpret this probability. Select the correct choice below and fill in the answer box within your choice. (Round to the nearest integer as needed.) A. If 100 pregnant individuals were selected independently from this population, we would expect pregnancies to last exactly 188 days. O B. If 100 pregnant individuals were selected independently from this population, we would expect 35 pregnancies to last less than 188 days. C. If 100 pregnant individuals were selected independently from this population, we would expect pregnancies to last more than 188 days. (b) Suppose a random sample of 18 pregnancies is obtained. Describe the sampling distribution of the sample mean length of pregnancies. The sampling distribution of x is = 194 and o; = 3.7712. normal with (Round to four decimal places as needed.) (c) What is the probability that a random sample of 18 pregnancies has a mean gestation period of 188 days or less? The probability that the mean of a random sample of 18 pregnancies is less than 188 days is approximately .0558 . (Round to four decimal places as needed.) Interpret this probability. Select the correct choice below and fill in the answer box within your choice. (Round to the nearest integer as needed.) A. If 100 independent random samples of size n= 18 pregnancies were obtained from this population, we would expect sample(s) to have a sample mean of 188 days or less. O B. If 100 incdenendent random camples of cize n – 12 nreanancies were ohtained from thie nonulation Lwe would evp ect camplelel to have a sample mean of 188 dave or more
Jun 04, 2022
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