Suppose that we define triple 3DES with a 168-bit key as
C = E(E(E(P,K1),K2),K3).
Suppose that we can compute and store a table of size 256, and a chosen plaintext attack is possible. Show that this triple 3DES is no more secure than the usual 3DES, which only uses a 112-bit key. Hint: Mimic the meet-in-the-middle attack on double DES.
Already registered? Login
Not Account? Sign up
Enter your email address to reset your password
Back to Login? Click here