Suppose that the lengths of text messages are normally distributed with an unknown mean and standard deviation. A random sample of 18 text messages is taken and gives a sample mean of 25 characters...


Suppose that the lengths of text messages are normally distributed with an unknown mean and standard deviation. A<br>random sample of 18 text messages is taken and gives a sample mean of 25 characters and a sample standard deviation of<br>2 characters.<br>df to.10to.os 0.25 t0.01<br>0.025<br>16 1.337 1.746 2.120 2.583 2.921<br>17 1.333 1.740 2.110 2.567 2.898<br>18 1.330 1.734 2.101 2.552 2.878<br>19 1.328 1.729 2.093 2.539 2.861<br>20 1.325 1.725 2.086 2.528 2.845<br>(a) Find the margin of error, for a 95% confidence interval estimate for the population mean using the Student's.<br>distribution.<br>Use the portion of the table above. Round the final answer to two decimal places.<br>Provide your answer below:<br>ME-<br>

Extracted text: Suppose that the lengths of text messages are normally distributed with an unknown mean and standard deviation. A random sample of 18 text messages is taken and gives a sample mean of 25 characters and a sample standard deviation of 2 characters. df to.10to.os 0.25 t0.01 0.025 16 1.337 1.746 2.120 2.583 2.921 17 1.333 1.740 2.110 2.567 2.898 18 1.330 1.734 2.101 2.552 2.878 19 1.328 1.729 2.093 2.539 2.861 20 1.325 1.725 2.086 2.528 2.845 (a) Find the margin of error, for a 95% confidence interval estimate for the population mean using the Student's. distribution. Use the portion of the table above. Round the final answer to two decimal places. Provide your answer below: ME-

Jun 01, 2022
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