Statistics show that 43% of men exercise daily and 68% of women do. A random sample of 70 men indicated 28 exercised daily and of 90 women surveyed 35 indicated they exercise daily. Construct a 98% confidence interval for the true difference of proportions of men and women who exercise daily.
Sample1= men, Sample2=women
(a) 98% confidence interval for the true difference of proportions of men and women who exercise daily. Round your answer to nearest ten-thousandth.
Round confidence interval to the nearest ten-thousandth if necessary. (e.g. 0.12456 would be entered as 0.1246)
Lower , Upper
(b) From the result of question (a). which sample has larger proportion or is it not much different?(input as "men", "women" or "same" )
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