View more »
Answered 2 days AfterMay 03, 2023

Answer To:

Baljit answered on May 06 2023
39 Votes
Question 1:-
    Groups
    Frequencies
    Grouped Mean
    Cumulative Frequency
    300
    to
    307
    12
    303.5
    12+0=12
    307
    to
    314
    18
    
    12+18=30
    314
    to
    321
    44
    
    30+44=74
    321
    to
    328
    88
    =324.5
    74+88=162
    328
    to
    335
    86
    =331.5
    162+86=248
    335
    to
    342
    41
    
    
248+41=289
    342
    to
    349
    15
    
    289+15=304
    349
    to
    356
    9
    =352.5
    304+9=313
1.

2.
Mean:
Standard Deviation:
s
Sd=
Median:-
Middle Value (N/2)=313/2=156.5
Now Middle Values lies between 321-328
Here l is lower limit of median class =321
Cf is cumulative frequency of class preceding the median class
F is frequency of median class =88
h is class size =7
So
327.5625
First Quartile:
N/4 i.e 313/4=78.25 lies between interval 321-328
*7=321.33
Third Quartile:
3N/4=4*313/4=234.75 lies in interval 328-335
*7=333.92
3.
As we can see from the mean and median which are equal to each other So that mean data distribution is symmetric. Same we can see it from the frequency polygon and histogram that data is symmetric.
    
4. The mean and standard deviation for grouped data are calculated by treating each interval as a single value (the midpoint) and using the same formulas as for ungrouped data. The formula for mean is the weighted average of the midpoints, where the weights are the frequencies. The formula for standard deviation is the square root of the weighted average of the squared deviations from the mean, where the weights are the frequencies.
5. If a continuous data is follow normal distribution then 68.2%, 95.4%, and 99.7% observations are lie between
mean ± 1 SD, mean ± 2 SD, and mean ± 3 SD, respectively.
i. Now 68.2% observation is =0.682*313=213.466
Which is lies in interval 328-335
Now
Mean ± 1 SD=327.4744 ± 10.46 is 317.0144 to 337.93
So 68.2 % observation lies between mean ± 1 SD
ii. Now 95.4% observation is =0.954*313=298.602
Which is lies in interval 342-349
Now
Mean ± 2 SD=327.4744 ± 2* 10.46 is 306.5544 to 348.4944
So 95.4 % observation lies between mean ± 2 SD
iii. Now 99.7% observation is =0.997*313=312.06
Which is lies in interval 349-356
Now
Mean ± 3 SD=327.4744 ± 3* 10.46 is 296.09 to 358.8544
So 99.7 % observation lies between mean ± 3 SD
Hence our distribution is normal distribution.
Question 2:-
Part(a)
1.
Sample Mean (
Sample Standard Deviation,
Sample Standard Deviation,
Sample Standard Deviation,
We are using term sample mean and standard deviation because it is the mean and standard deviation of a small sample of the Population.
2. We will use Z-test Hypothesis
To calculate Z
Here
: Sample Mean
Standard deviation
So for calculation of the Z value we need sample mean
3. Now
For significance level
Z Critical Value for ,
Now Since
Hence we failed to Reject Null Hypothesis So we don’t have sufficient evidence to claim that mean is not 200mm
Part(b)
1. Sample Mean (
Sample Standard Deviation,
Sample Standard Deviation,
Sample...
SOLUTION.PDF

Answer To This Question Is Available To Download

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here
April
January
February
March
April
May
June
July
August
September
October
November
December
2025
2025
2026
2027
SunMonTueWedThuFriSat
30
31
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
1
2
3
00:00
00:30
01:00
01:30
02:00
02:30
03:00
03:30
04:00
04:30
05:00
05:30
06:00
06:30
07:00
07:30
08:00
08:30
09:00
09:30
10:00
10:30
11:00
11:30
12:00
12:30
13:00
13:30
14:00
14:30
15:00
15:30
16:00
16:30
17:00
17:30
18:00
18:30
19:00
19:30
20:00
20:30
21:00
21:30
22:00
22:30
23:00
23:30