Solve the system by the elimination method. (Enter your answers as a comma-separated list. If the system is inconsistent, enter INCONSISTENTly. If the system is dependent, enter DEPENDENT.) NI( -= {3x...

Q5: -
Sol: -
2 5 35 .........................(1)
2 3 29 .........................(2)
x y
x y
 
 

Now, using elimination method we will perform (1) (2)eq eqand we get
2 6y 
  3 3y 
Putting eq(3) in eq(1) we get
  2 5 3 35x 
2 15 35x 
  0 41x 
Hence, solution will be    , 10,3x y 
Q6: -
Sol:-
,
of $3000
of $6000
Let
Number Investor contributed be x
Number Investor contributed be y

Now,
Statement 1: - Number of investors are 60
 60x y 
Statement 2: - Total amount contributed $264,000
3000 6000 264000x y 
 2 88x y 
Now, we have
60 .........................(1)
2 88 .........................(2)
x y
x y
 
 
Now, using elimination method we will perform (2) (1)eq eq and we get
  8 32y 
Putting eq(3) in eq(1) we get
 28 60x 
  2 43x 
Thus,
of $3000 =32
of $6000 = 28
Number Investor contributed
Number Investor contributed
Q7: -
28y 
Sol:-
,
of
of dim y
Let
Number nickel be x
Number e be

Now,
Statement 1: - Number of coins are 70
 70x y 
Statement 2: - Total amount contributed $5.9
5 10 590x y 
Now, we have
70 .........................(1)
5 10 590 .........................(2)
x y
x y
 
 
Now, using elimination method we will perform (2) 5 (1)eq eq and we get

  8 34y 
Putting eq(3) in eq(1) we get
 48 70x 
  2 42x 
Thus,
of = 48
dim = 22
Number nickel
Number of e
Q8: -
Sol: -
,
of soda bottle sold
of hot dogs sold y
Let
Number be x
Number be

Now,
Statement 1: - Total sold items ...