MATH2004C Assignment 1 Last Name: First Name: Student ID: • You may either write your answers on a copy of this assignment, or on your own paper or on your electronic devices (you do not need to copy...

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Answered 1 days AfterFeb 05, 2022

Answer To: MATH2004C Assignment 1 Last Name: First Name: Student ID: • You may either write your answers on a...

Sudarshan K answered on Feb 06 2022
109 Votes
Math 2004C
1) Equation of planes the passes through points A(2,3,-1), B(3,4,2) and C(1,-1,0)
a. Equation of line
Equation of three dimensional plane can be given by ax+by+cz+d=0
By plugging the
points in the plane equation,
Point A:
2a+3b-c+d=0 ----(1)
Point B:
3a+4b+3c+d=0 -----(2)
Point C:
a-b+d=0 -------(3)
Solving this equation.
a=b-d
Subs. it in (1)
5b-c-d=0 c=5b-d
Subs a and c in (2)
3(b-d)+4(b)+3(5b-d)+d=0 22b-5d=0 b=5d/22, a = -17d/22, c=3d/22
Subs. a, b, c in plane equation.
-17/22 (dx)+5/22 (dy)+3/22(dz)+d=0
Cancelling d and multiplying by 22
-17x+5y+3z+22=0 is the equation of plane passing though point A,B and C
b. Equation of plane through point (1,2,3) and parallel to the plane (4x-3y+2z=1).
Equation of plane parallel to plane 4x-3y+2z=1 is given by
4x-3y+2z=a
Subs point A(1,2,3) in above equation
4-6+6=a a=4
So final equation is 4x-3y+2z=4
2) Find a parameterization of the line in space that intersect the planes 2x+y-3z=0 and x+y=1.
Plane A=2x+y-3z =0, plane B =x+y=1
Normal vector of plane A <2,1,-3> and normal vector of plane B<1,1,0>
Cross product of the above two vectors give
AxB =    | i j k |
    | 2 1 -3 |
    | 1 1 0 |
AxB=3i-3j+k
So normal vector of the cross product is <3, -3, 1>
By taking the value of y as zero for finding the plane
Plane B gives x=1.
Subs. it in plane A, gives z=2/3
So the vector becomes <1, 0, 2/3>
So the parameterization equation can be given by
(1+3t)i+(0-3t)j+(2/3+t)k
So the x, y, and z values are given by
X=1+3t, y = -3t, z =2/3+t
3) A curve space is given at triangle that begins at A(-1,0,7) to B(5,4,-2), from B(5,4,-2) to C(-3,1,4) and from point C to point A. Find parameterization of three curves given by these 3 lines depending upon ‘t’ and within 0Answer:
For line 1 from A to B so it is starting from point A and moving towards point B. So the starting point can be taken as point A and then using the difference between two points
V=
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