Solve the circuit in Figure 14 using the resistance and reactance values in Table 1 for the total active, reactive and apparent powers in the circuit. Phases 2 and 3 are the same as in Step 7, but...


Solve the circuit in Figure 14 using the resistance and<br>reactance values in Table 1 for the total active, reactive and<br>apparent powers in the circuit. Phases 2 and 3 are the same<br>as in Step 7, but phase 1 is now as shown at right with<br>E1-N = 120 Vrms<br>IPhasel<br>3002<br>E1-N<br>-j600 N<br>PT<br>QT<br>ST<br>

Extracted text: Solve the circuit in Figure 14 using the resistance and reactance values in Table 1 for the total active, reactive and apparent powers in the circuit. Phases 2 and 3 are the same as in Step 7, but phase 1 is now as shown at right with E1-N = 120 Vrms IPhasel 3002 E1-N -j600 N PT QT ST
Table 1. Resistance and capacitive reactance values used for unbalancing the four-wire, wye-<br>connected, three-phase circuit of Figure 14.<br>Local ac power network<br>R1<br>(Q)<br>Rz, R3<br>(Q)<br>Xc2, Xc3<br>(0)<br>Voltage<br>(V)<br>120<br>Frequency<br>(Hz)<br>(2)<br>60<br>300<br>171<br>600<br>240<br>220<br>50<br>1100<br>629<br>2200<br>880<br>240<br>50<br>1200<br>686<br>2400<br>960<br>

Extracted text: Table 1. Resistance and capacitive reactance values used for unbalancing the four-wire, wye- connected, three-phase circuit of Figure 14. Local ac power network R1 (Q) Rz, R3 (Q) Xc2, Xc3 (0) Voltage (V) 120 Frequency (Hz) (2) 60 300 171 600 240 220 50 1100 629 2200 880 240 50 1200 686 2400 960

Jun 11, 2022
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