Shown in Fig. P4.8 is the ac equivalent of a currentdriven CE amplifi er. Let the BJT have gm 5 1y(10 V), r5 1.5 kV, ro 5 30 kV, and r5 18 MV, and let ib be a 1-A ac current. (a) Find the ac voltages...

Shown in Fig. P4.8 is the ac equivalent of a currentdriven CE amplifi er. Let the BJT have gm 5 1y(10 V), r5 1.5 kV, ro 5 30 kV, and r5 18 MV, and let ib be a 1-A ac current. (a) Find the ac voltages vb, ve, and vc, if RE 5 0 and RL 5 `. To see the effect of r, calculate fi rst assuming r5 `, then using r5 18 MV. Note that ris subject to the Miller effect, so refl ected to the base rgets divided by 1 2 a, where a 5 vcyvb. (b) Repeat part (a), but with an output load RL 5 ro 5 30 kV. (c) Repeat parts (a) and (b), but with an emitterdegeneration resistance RE 5 0.5 kV.