Show, using simulations, that if the output of the comparator swings from VDD to VDD/2 we can eliminate M4 in Fig. 17.9 and still have Q cup =C cup ■ (VDD V REF - V THP ). Why? Does the amount of...

Show, using simulations, that if the output of the comparator swings from VDD to VDD/2 we can eliminate M4 in Fig. 17.9 and still have Q
_cup
=C
_cup
■ (VDD V_REF
- V_THP). Why? Does the amount of current supplied by VDD/2 increase? Could this be a problem?