Show that the trade off between the average and maximum distance— the center-median trade off—can be found by solving a series of P-median problems in which the constraint that the maximum distance is less than or equal to Qm-1max-1 on iteration m is represented by adding a (very) large constant to all distances greater than or equal to Qm-1max. Explain why this approach will work and why the two approaches— explicitly adding constraint (8.14) and adding a constant to all distances greater than or equal to Qm-1max-are equivalent.
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