Show that the moment of inertia of a disk of mass M and radius R is . Divide the disk into narrow rings, each of
radius r and width dr. The contribution to I by one of these rings is simply r2 dm, where dm is the amount of mass contained
in that particular ring. The mass of any ring is the total mass times the fraction of the total area occupied by the area of the
ring. The area of this ring is approximately 2πrdr. Use integral calculus to add up all the contributions.
Sections 9.5, 9.6
Already registered? Login
Not Account? Sign up
Enter your email address to reset your password
Back to Login? Click here