Show that for arbitrary a, b, u > 0 one has                           (a + u) 2 a + b · u ≥  a + b−2 b a 2 a + b b−2 b a = 4ab − 1 b2 . Hint: Show that the function...


Show that for arbitrary a, b, u > 0 one has


                          (a + u) 2 a + b · u ≥  a + b−2 b a 2 a + b b−2 b a = 4ab − 1 b2 .


Hint: Show that the function


                              f(u) = (a + u) 2 a + b · u


satisfies


                              f (u) <><>


and


                               f(u) > 0 if u > b − 2 b · a.



May 23, 2022
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