Show complete solution. Round everything to four decimal places and box all final answers. The molar heat of formation of NH4N03 (s) is -367.54 KJ and those of N20 (g) and H20 (1) are 81.46 and -285.8...

Show complete solution. Round everything<br>to four decimal places and box all final<br>answers.<br>The molar heat of formation of<br>NH4N03 (s) is -367.54 KJ and those of<br>N20 (g) and H20<br>(1) are 81.46 and -285.8 KJ respectively at<br>25°C and 1 atmospheric pressure.<br>Calculate<br>delta H and delta U of reaction.<br>NH4NO3(s) → N20(g) + H20(I)<br>

Extracted text: Show complete solution. Round everything to four decimal places and box all final answers. The molar heat of formation of NH4N03 (s) is -367.54 KJ and those of N20 (g) and H20 (1) are 81.46 and -285.8 KJ respectively at 25°C and 1 atmospheric pressure. Calculate delta H and delta U of reaction. NH4NO3(s) → N20(g) + H20(I)

Jun 11, 2022

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Show complete solution. Round everything to four decimal places and box all final answers. The molar heat of formation of NH4N03 (s) is -367.54 KJ and those of N20 (g) and H20 (1) are 81.46 and -285.8...

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