Shift log ( 25 25 10 log Pin (2) PinmW= 10" -1000 Dinmw = 316.22 9- The diagram below represents the first three stages of a typical AM or FM receiver. Find the following quantities. antenna aerial...

Extracted text: Shift log ( 25 25 10 log Pin (2) PinmW= 10" -1000 Dinmw = 316.22 9- The diagram below represents the first three stages of a typical AM or FM receiver. Find the following quantities. antenna aerial Pout A Pz Pin مسقبل reciver 7attenuator P3 ) P,=1 pW REAmplifier Ar=100 Mixer IF Amplifier Pnt Ap=10,000 -17 Apz=0.2 %3D Pout AT= pico watts -12 a) Arand AT dB-. Pin b) Ap1,aB, Ap2,dB and Ap2,dB- c) Pz, Pzand Pout. d) Pin,dBm, P1aBm, P2,aBm and Pout,dBm Pw = 1XI0 w %3D Pout =ATx Pin gconvertion to Bm Q: a) total gain ) )P,= Pin X Ap Ĉ Ap, (Cas cade System P= Ipwx 100