SEE ATTACHED FILE - Find bases for the column space of A, row space of A, and null space of a. Document Preview: Find bases for the column space of A, row space of A, and null space of a. verify that...

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Answered Same DayDec 29, 2021

Answer To: SEE ATTACHED FILE - Find bases for the column space of A, row space of A, and null space of a....

David answered on Dec 29 2021
131 Votes
ANSWERS:
1. Find bases for the column space of A, row space of A, and null space of a. verify that
rank/nullity theorem holds. ( A is 4x4)
A= [[1,4,-1,1][3,11,
-1,4][1,5,2,3][2,8,-2,2]
We first reduce the matrix to reduced row echelon form(RREF).
By the following operations,
add -4 times the 1st row to the 2nd row
add 1 times the 1st row to the 3rd row
add -1 times the 1st row to the 4th row
multiply the 2nd row by -1
add -2 times the 2nd row to the 3rd row
add -1 times the 2nd row to the 4th row
multiply the 3rd row by 1/5
add -3 times the 3rd row to the 4th row
add 1 times the 3rd row to the 2nd row
add -1 times the 3rd row to the 1st row
add -3 times the 2nd row to the 1st row
Rref(A) =[[1,0,0,2][0,1,0,0][0,0,1,0][0,0,0,0]]
The fourth column is a linear combination of the 1
st
column.
So, the basis for the column space are the remaining column vectors in the rref(A) =
[1,0,0,0] , [0,1,0,0] and [0,0,1,0].
Similarly, row space has the basis as: [1,0,0,2] , [0,1,0,0] and [0,0,1,0].
For the nullspace, Ax=0 or equivalently, rref(A)x=0,
If x [x1,x2,x3,x4], we have,
x = [-2x4,0,0,x4]. Thus, [-2,0,0,1] is the basis for the nullspace.
Dimension of column space= Dimension of row space =Rank of A=3
Dimension of null space =1.
3+1 =4 = Dimension of A .Thus the rank-nullity equation is verified.
2. Use cramers rule to find solution. If no solution explain why
X1 +x2 -2x3 = -3
3*x1-2*x2+2*x3 = 9
6*x1 -7*x2-x3 = 4
Evaluating the determinants we get
Δ= 49
Δx= 79
Δy=22
Δz= 124
Thus, x= Δx /Δ=79/49
y= Δy /Δ=22/49
z= Δz /Δ=124/49
3. Find adj(A) and use it to compute...
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