Scoring for Lab 6: Screen shot – 10 points Activity Data Code – 5 points Data Tables – 15 points Question Completion – 20 points Random Questions Scored – 50 points · On your own and without...

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Scoring for Lab 6: Screen shot – 10 points Activity Data Code – 5 points Data Tables – 15 points Question Completion – 20 points Random Questions Scored – 50 points  · On your own and without assistance, complete this Lab Activity Form electronically and submit it via the Assignments Folder by the date listed in the Course Schedule (under Syllabus). · Answer ALL questions in your own words. If a direct quote is needed, put the words in quotation marks and cite the source. · To conduct the laboratory exercises, use the Table Top Science link located under Course Content. Read the background information and the directions for each exercise/experiment carefully before completing the exercises/experiments and answering the questions. · Students should submit the document as a Word (.doc or .docx) or PDF file to the assignment folder for best compatibility. · If screen shots are missing, the lab earns 0 points until it is included. Data Sheet: Activity - Genetics All Content is Copyright Protected and May NOT Be Posted or Shared Outside Of The Classroom Name Course Date Activity Data Code       Take a screenshot of your results. Insert the picture here: Procedure I – Students will sample a population of baby bugs and record the genotype and phenotype of their parents. Students will then solve a Punnett Square using the genotypes of the parent bugs to learn what the expected percentages of each genotype and phenotype of the baby bugs would be based on 4 offspring. Last, students compare the expected results from the Punnett Square with the actual results from the lab activity. Procedure I - Part A - Baby bugs when parents are BB and bb 4 TableTop Science – All Rights Reserved 1 TableTop Science – All Rights Reserved Data Table - Enter your Baby Bug Counts BB Baby Bug Count Bb Baby Bug Count bb Baby Bug Count Percentage Tables - Enter the Baby Bug percentages Tip: Baby Bug Percentage = 100% (Baby Bug Count) / (Total Number of Baby Bugs) BB Baby Bug Percentage Bb Baby Bug Percentage bb Baby Bug Percentage Tip: Blue Rimmed Baby Bug Percentage = BB Baby Bug Percent + Bb Baby Bug Percent Blue Rimmed Baby Bug Percentage Yellow Rimmed Baby Bug Percentage Observations and Questions [1] Complete the Punnett square below when the parents are BB and bb. Punnett Square Male Female Alleles/Genes B B [2] Describe your baby bug results from this data run in terms of genotypes and phenotypes. A. Genotypes – B. Phenotypes - [3] Why are there no BB baby bugs or bb baby bugs from this data run? [4] Do the results for the allele distributions in the first 3 data tables confirm the entries in your Punnett Square? (For example, is the percentage of BB baby bugs in the count from the lab activity similar to the expected percentage of BB baby bugs based on the Punnet Square) A. Yes or No? B. Please explain why. [5] What evidence from this data run supports the hypothesis that the B allele is heterozygous dominant? If the lab didn’t tell students that “B” is the dominant allele, how would you know from the characteristics of the parents and offspring that “B” is dominant? Explain your reasoning. Procedure I - Part B - Baby bugs when parents are bb and Bb 2 TableTop Science – All Rights Reserved 3 TableTop Science – All Rights Reserved Data Table - Enter your Baby Bug Counts from each data run Data Run BB Baby Bug Count Bb Baby Bug Count bb Baby Bug Count 1 2 3 4 5 6 7 8 9 10 Data Averages Table - Enter your average Baby Bug Counts Tip: BB Baby Bug Count Average = Sum of BB Baby Bug Counts / Number of Data Runs BB Baby Bug Count Average Bb Baby Bug Count Average bb Baby Bug Count Average Percentage Tables - Enter the Baby Bug percentages Tip: Baby Bug Percent = 100% (Baby Bug Count Average) / (Total Number of Baby Bugs) BB Baby Bug Percentage Bb Baby Bug Percentage bb Baby Bug Percentage Tip: Blue Rimmed Baby Bug Percentage = BB Baby Bug Percent + Bb Baby Bug Percent Blue Rimmed Baby Bug Percentage Yellow Rimmed Baby Bug Percentage Observations and Questions [6] Complete the Punnett square below when the parents are bb and Bb. Punnett Square Male Female Alleles/Genes b b [7] A. Using your Punnett Square, calculate the expected percentage of Blue Rimmed Baby Bugs and Yellow Rimmed Baby Bugs. Show your work. B. How do your percentage table results compare with the Punnett Square calculations? (higher, lower, similar) C. Explain your answer. [8] Why do we use multiple data runs for this procedure? Explain why using multiple data runs provides a better answer. [9] A. For this set of parents, is it possible to draw conclusions about the genotype counts from examining the phenotypes? B. Why or why not? Use counts from one of your BB vs Bb data runs as part of your discussion. Procedure I - Part C - Baby bugs when parents are Bb and Bb Data Table - Enter your Baby Bug Counts from each data run Data Run BB Baby Bug Count Bb Baby Bug Count bb Baby Bug Count 1 2 3 4 5 6 7 8 9 10 Data Averages Table - Enter your average Baby Bug Counts Tip: BB Baby Bug Count Average = Sum of BB Baby Bug Counts / Number of Data Runs BB Baby Bug Count Average Bb Baby Bug Count Average bb Baby Bug Count Average Percentage Tables - Enter the Baby Bug percentages Tip: Baby Bug Percent = 100% (Baby Bug Count Average) / (Total Number of Baby Bugs) BB Baby Bug Percentage Bb Baby Bug Percentage bb Baby Bug Percentage Tip: Blue Rimmed Baby Bug Percentage = BB Baby Bug Percent + Bb Baby Bug Percent Blue Rimmed Baby Bug Percentage Yellow Rimmed Baby Bug Percentage Observations and Questions [10] Complete the Punnett square below when the parents are Bb and Bb. Punnett Square Male Female Alleles/Genes B b [11] A. Using your Punnett Square, calculate the expected percentage of Blue Rimmed Baby Bugs and Yellow Rimmed Baby Bugs. Show your work. B. How do your percentage table results compare with the Punnett Square calculations? (higher, lower, similar) Explain your answer. [12] For Bb vs Bb parents, discuss how the genotype counts confirm the counts for the phenotypes in the display. Be specific. Use counts from one of your Bb vs Bb data runs as part of your discussion. Procedure II – Students will learn about 2 causes of evolution. They will then sample populations of baby bugs to see if evolution took place by analyzing the difference in the genotypes and phenotypes of baby bugs compared to the genotypes and phenotypes of baby bugs in Procedure I. Procedure II - Part A - Bug Population changes when there is a breeding preference for blue rimmed bugs [13] Define Natural Selection in your own words. [14] You are an entomologist and have been studying the predator-prey relationship of the Swift Winged Bug Catcher and the Rimmed Bugs. Both organisms live in grassy fields dominated by green perennial plants. One summer was very dry and yellow plants flourished while the green plants died off. The entomologist found at the end of the summer that there were far more Yellow Rimmed Bugs than are normally in this population. A. Is this an example of Natural Selection? B. Please explain why or why not. C. What do you expect to happen to the population of bugs if the drought continues? 4 TableTop Science – All Rights Reserved 5 TableTop Science – All Rights Reserved Data Table - Enter your Final Bug Counts BB Bug Count Bb Bug Count bb Bug Count Percentage Tables - Enter the Final Bug percentages Tip: Bug Type Percentage = 100% (Bug Type Count) / (Total Number of Bugs) BB Bug Percentage Bb Bug Percentage bb Bug Percentage Tip: Blue Rimmed Baby Bug Percentage = BB Bug Percent + Bb Bug Percent Blue Rimmed Bug Percentage Yellow Rimmed Bug Percentage Observations and Questions [15] Describe the bug population change results during this data run in terms of genotypes and phenotypes. A. Genotypes - B. Phenotypes - [16] A. Do your results suggest anything about what the composition of this population might be at some distant point in the future? B. Defend your answer. Procedure II - Part B - Bug Population changes when there is not a rim-color breeding preference for bugs (genetic drift) [17] Define “Genetic Drift” in your own words. [18] You are an entomologist studying these bugs and you’d like to raise a population of these bugs in your lab. You go out to the woods where these bugs live, and with one swipe of an insect net, capture 21 bugs and bring them back to your lab. A. Is this an example of Genetic Drift? B. Explain why or why not C. What do you expect will happen to the percentages of Blue Rimmed and Yellow Rimmed bugs in your lab population compared to the wild population of bugs? 14 TableTop Science – All Rights Reserved 13 TableTop Science – All Rights Reserved Data Table - Enter your Final Bug Counts BB Bug Count Bb Bug Count bb Bug Count Percentage Tables - Enter the Final Bug percentages Tip: Bug Type Percentage = 100% (Bug Type Count) / (Total Number of Bugs) BB Bug Percentage Bb Bug Percentage bb Bug Percentage Tip: Blue Rimmed Baby Bug Percentage = BB Bug Percent + Bb Bug Percent Blue Rimmed Bug Percentage Yellow Rimmed Bug Percentage Observations and Questions [19] Describe the bug population change results during this data run in terms of genotypes and phenotypes. A. Genotypes – B. Phenotypes - Note: The question below depends on sharing and comparing Procedure II - Part B data with your fellow classmates. Please go to Content – Week 6 – Week 6 Virtual Lab – Data for Lab 6 Discussion and post your data as a response to that discussion topic. [20] A. Compare your data run results for Genetic Drift in Procedure II part B to the results of the class as a whole. What population changes are possible? B. Are there any cases of extreme changes in population composition (e.g. all blue-rimmed or all yellow-rimmed)? C