s] A random sample of 20 nominally measured of the length of a plastic ball is taken and the lengths are measured precisely. The measurements, in mm, are as follows: 2.02 1.94 2.09 1.95 1.98 2.00 1.03...


s] A random sample of 20 nominally measured of the length of a plastic ball is taken and<br>the lengths are measured precisely. The measurements, in mm, are as follows:<br>2.02 1.94 2.09 1.95 1.98 2.00 1.03 2.04 2.08 2.07<br>1.99 1.96 1.99 1.95 1.99 1.99 2.03 2.05 2.01 2.03<br>From the data, we calculate EX = 39.19, Ex² = 77.7377<br>Assuming that the lengths are normally distributed with unknown mean µ, and unknown variance 82<br>i.<br>find a 90% confidence interval for the variance o?. Interpret your results.<br>ii.<br>find a 90% confidence interval for the standard deviation o . Interpret your results.<br>

Extracted text: s] A random sample of 20 nominally measured of the length of a plastic ball is taken and the lengths are measured precisely. The measurements, in mm, are as follows: 2.02 1.94 2.09 1.95 1.98 2.00 1.03 2.04 2.08 2.07 1.99 1.96 1.99 1.95 1.99 1.99 2.03 2.05 2.01 2.03 From the data, we calculate EX = 39.19, Ex² = 77.7377 Assuming that the lengths are normally distributed with unknown mean µ, and unknown variance 82 i. find a 90% confidence interval for the variance o?. Interpret your results. ii. find a 90% confidence interval for the standard deviation o . Interpret your results.

Jun 08, 2022
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