s) = (1 – p)s. (Hint: The probability that more than s trials are neededto obtain the first success is equal to the probability that the first s trials are allfailures.)a.b.Let t 2 0 be an...


Let X - Geom(p). Let s 2 0 be an integer.<br>Show that P(X > s) = (1 – p)s. (Hint: The probability that more than s trials are needed<br>to obtain the first success is equal to the probability that the first s trials are all<br>failures.)<br>a.<br>b.<br>Let t 2 0 be an integer. Show that P(X >s + 1 | X > s) = P(X > t). This is the<br>memoryless property .[Hint: P(X > s + t and X > s) = P(X > s + t).]<br>A penny and a nickel are both fair coins. The penny is tossed three times and comes up<br>tails each time. Now both coins will be tossed twice each, so that the penny will be<br>tossed a total of five times and the nickel will be tossed twice. Use the memoryless<br>property to compute the conditional probability that all five tosses of the penny will be<br>tails, given that the first three tosses were tails. Then compute the probability that both<br>tosses of the nickel will be tails. Are both probabilities the same?<br>C.<br>

Extracted text: Let X - Geom(p). Let s 2 0 be an integer. Show that P(X > s) = (1 – p)s. (Hint: The probability that more than s trials are needed to obtain the first success is equal to the probability that the first s trials are all failures.) a. b. Let t 2 0 be an integer. Show that P(X >s + 1 | X > s) = P(X > t). This is the memoryless property .[Hint: P(X > s + t and X > s) = P(X > s + t).] A penny and a nickel are both fair coins. The penny is tossed three times and comes up tails each time. Now both coins will be tossed twice each, so that the penny will be tossed a total of five times and the nickel will be tossed twice. Use the memoryless property to compute the conditional probability that all five tosses of the penny will be tails, given that the first three tosses were tails. Then compute the probability that both tosses of the nickel will be tails. Are both probabilities the same? C.
Jun 10, 2022
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