Run a regression analysis on the following bivariate set of data with y as the response variable. y 40 47.7 50.5 28.1 34.1 34.2 29.7 64.1 6.7 65.4 28.9 40.1 30 32.9 19.3 51 24.8 39.1 22.2 40.9 13.5...


Run a regression analysis on the following bivariate set of data with y as the response variable.<br>y<br>40<br>47.7<br>50.5<br>28.1<br>34.1<br>34.2<br>29.7<br>64.1<br>6.7<br>65.4<br>28.9<br>40.1<br>30<br>32.9<br>19.3<br>51<br>24.8<br>39.1<br>22.2<br>40.9<br>13.5<br>53.3<br>22.9<br>42.6<br>Find the correlation coefficient and report it accurate to three decimal places.<br>r =<br>the values of x? Report<br>What proportion of the variation in y can be explained by the variation<br>answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be<br>84.5%..you would enter 84.5 without the percent symbol.)<br>r2 =<br>Based on the data, calculate the regression line (each value to three decimal places)<br>y =<br>Predict what value (on average) for the response variable will be obtained from a value of 7.3 as the<br>explanatory variable. Use a significance level of a<br>0.05 to assess the strength of the linear<br>correlation.<br>What is the predicted response value? (Report answer accurate to one decimal place.)<br>y =<br>

Extracted text: Run a regression analysis on the following bivariate set of data with y as the response variable. y 40 47.7 50.5 28.1 34.1 34.2 29.7 64.1 6.7 65.4 28.9 40.1 30 32.9 19.3 51 24.8 39.1 22.2 40.9 13.5 53.3 22.9 42.6 Find the correlation coefficient and report it accurate to three decimal places. r = the values of x? Report What proportion of the variation in y can be explained by the variation answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%..you would enter 84.5 without the percent symbol.) r2 = Based on the data, calculate the regression line (each value to three decimal places) y = Predict what value (on average) for the response variable will be obtained from a value of 7.3 as the explanatory variable. Use a significance level of a 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y =

Jun 08, 2022
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