Round-off intermediate values to 7 decimal places, and 5 decimal places for the final answer. Determine one real root of h (x) = ln| x³ –8 = -3 between -0.9 and -0.2 using the Bisection Method....

Round-off intermediate values to 7 decimal places, and 5 decimal places for the final answer.<br>Determine one real root of h (x) = ln|<br>x³ –8<br>= -3<br>between -0.9 and -0.2 using the Bisection Method.<br>Compute the error based on 2 significant figures (use the formula for Es).<br>How many iterations were needed to find the answer?<br>

Extracted text: Round-off intermediate values to 7 decimal places, and 5 decimal places for the final answer. Determine one real root of h (x) = ln| x³ –8 = -3 between -0.9 and -0.2 using the Bisection Method. Compute the error based on 2 significant figures (use the formula for Es). How many iterations were needed to find the answer?

Jun 05, 2022

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Round-off intermediate values to 7 decimal places, and 5 decimal places for the final answer. Determine one real root of h (x) = ln| x³ –8 = -3 between -0.9 and -0.2 using the Bisection Method....

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