Repeat problem 6.15 for a Hamiltonian tour in which the branch probabilities are all different. Instead of the binomial distribution, you will have to write out a series of terms that yields a formula...

Repeat problem 6.15 for a Hamiltonian tour in which the branch probabilities are all different. Instead of the binomial distribution, you will have to write out a series of terms that yields a formula different from that of problem 6.15, but one that also reduces to the same formula for equal probabilities.

problem 6.15