QUESTIONS No. 60) – 64): Determine Xe for a PFR with no pressure drop when the reaction is reversible: 2A e B. The system is gas phase isothermal with an initial feed rate of A = 3 moles/min, initial...


QUESTIONS No. 60) – 64): Determine Xe for a PFR with no pressure drop when the<br>reaction is reversible: 2A e B. The system is gas phase isothermal with an initial feed<br>rate of A = 3 moles/min, initial concentration of A = 0.1 mol/dm?, k = 2 dm/mol-s, Ks<br>= 100 dm/mol.<br>60)The concentration of A at equilibrium is represented by:<br>a) Cae = Cao (1 – X,)<br>b) Cae<br>CAo(1-X)<br>c) Cae<br>CAo (1-2x,)<br>d)<br>(1+ex,)<br>(ex)<br>VAo(1-X,)<br>Cae<br>61)The concentration of B at equilibrium is represented by:<br>а) Све — 2Сло (1 — еX,) b) Сзе<br>eCao (1+X,)<br>Cao(1-X,)<br>CAo (1-2X,)<br>c) Cpe =<br>(1+ex.)<br>(1+ex,)<br>Cao (x.)<br>d) Cse =<br>(1+ex,)<br>62)The derived equation of finding the equilibrium constant is represented by:<br>а) к, —<br>Xe(1+Xe)<br>b) Ke =<br>c) Ke =<br>d)<br>2CA0(1-X,)

Extracted text: QUESTIONS No. 60) – 64): Determine Xe for a PFR with no pressure drop when the reaction is reversible: 2A e B. The system is gas phase isothermal with an initial feed rate of A = 3 moles/min, initial concentration of A = 0.1 mol/dm?, k = 2 dm/mol-s, Ks = 100 dm/mol. 60)The concentration of A at equilibrium is represented by: a) Cae = Cao (1 – X,) b) Cae CAo(1-X) c) Cae CAo (1-2x,) d) (1+ex,) (ex) VAo(1-X,) Cae 61)The concentration of B at equilibrium is represented by: а) Све — 2Сло (1 — еX,) b) Сзе eCao (1+X,) Cao(1-X,) CAo (1-2X,) c) Cpe = (1+ex.) (1+ex,) Cao (x.) d) Cse = (1+ex,) 62)The derived equation of finding the equilibrium constant is represented by: а) к, — Xe(1+Xe) b) Ke = c) Ke = d) 2CA0(1-X,)" (1+X,) CAo(1-ex,) K = 2(1-X) 63)The value of e is: a) 1 b) 1.5 64)The conversion of the reaction at equilibrium is: b) 0.82 c) 0.5 d) 2.0 a) 0.89 c) 0.84 d) 1.15

Jun 09, 2022
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