QUESTIONS No. 1) – 3): Consider the 3rd order reaction: 2NOG) + O2 (9) → 2NO2 (g). The specific rates of the reaction, expressed in moles/L-s are: For the forward reaction: @600 K, k = 6.63 x 105; For...


Please answer number 3. Thank you.


QUESTIONS No. 1) – 3): Consider the 3rd order reaction: 2NOG) + O2 (9) → 2NO2 (g).<br>The specific rates of the reaction, expressed in moles/L-s are:<br>For the forward reaction: @600 K, k = 6.63 x 105;<br>For the reverse reaction: @600 K, k = 83.9;<br>1) Calculate the equilibrium constant at 600K?<br>a) 7.6 x 103<br>2) Calculate the activation energy for the forward reaction?<br>a) 2.699 x 104<br>3) Calculate the frequency factor for the forward reaction?<br>a) 8.43 x 105<br>@645 K, k = 6.52 x 105<br>@645 K, k = 407<br>b) 7.9 x 103<br>c) 7.27 x 10-4<br>d) 6.25 x 104<br>b) 2.727 x 104<br>c) -2.859 x 102 d) 2.859 x 102<br>b) 3.23 х 104<br>с) 5.86 х 102<br>d) 2.59 x 103<br>

Extracted text: QUESTIONS No. 1) – 3): Consider the 3rd order reaction: 2NOG) + O2 (9) → 2NO2 (g). The specific rates of the reaction, expressed in moles/L-s are: For the forward reaction: @600 K, k = 6.63 x 105; For the reverse reaction: @600 K, k = 83.9; 1) Calculate the equilibrium constant at 600K? a) 7.6 x 103 2) Calculate the activation energy for the forward reaction? a) 2.699 x 104 3) Calculate the frequency factor for the forward reaction? a) 8.43 x 105 @645 K, k = 6.52 x 105 @645 K, k = 407 b) 7.9 x 103 c) 7.27 x 10-4 d) 6.25 x 104 b) 2.727 x 104 c) -2.859 x 102 d) 2.859 x 102 b) 3.23 х 104 с) 5.86 х 102 d) 2.59 x 103

Jun 10, 2022
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