Question Help ▼ A poll of 2,009 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 94% of adults own cell phones. Use...


Question Help ▼<br>A poll of 2,009 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 94% of adults own cell phones. Use the normal distribution as an<br>approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).<br>Test of p = 0.94 vs p + 0.94<br>Sample X<br>Sample p<br>95% CI<br>Z-Value<br>P-Value<br>1<br>1912<br>2,009<br>0.951717<br>(0.942344,0.961091)<br>2.21<br>0.027<br>O C. Ho: p>0.94<br>O D. Ho: p<0.94<br>Choose the correct answer below.<br>O A. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.<br>B. Reject the null hypothesis because the P-value is greater than the significance level, a.<br>OC. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.<br>O D. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.<br>e. What is the final conclusion?<br>O A. There is not sufficient evidence to warrant rejection of the claim that 94% of adults own a cell phone.<br>O B. There is sufficient evidence to warrant rejection of the claim that 94% of adults own a cell phone.<br>O C. There is sufficient evidence to support the claim that 94% of adults own a cell phone.<br>O D. There is not sufficient evidence to support the claim that 94% of adults own a cell phone.<br>

Extracted text: Question Help ▼ A poll of 2,009 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 94% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p = 0.94 vs p + 0.94 Sample X Sample p 95% CI Z-Value P-Value 1 1912 2,009 0.951717 (0.942344,0.961091) 2.21 0.027 O C. Ho: p>0.94 O D. Ho: p<0.94 choose="" the="" correct="" answer="" below.="" o="" a.="" reject="" the="" null="" hypothesis="" because="" the="" p-value="" is="" less="" than="" or="" equal="" to="" the="" significance="" level,="" a.="" b.="" reject="" the="" null="" hypothesis="" because="" the="" p-value="" is="" greater="" than="" the="" significance="" level,="" a.="" oc.="" fail="" to="" reject="" the="" null="" hypothesis="" because="" the="" p-value="" is="" less="" than="" or="" equal="" to="" the="" significance="" level,="" a.="" o="" d.="" fail="" to="" reject="" the="" null="" hypothesis="" because="" the="" p-value="" is="" greater="" than="" the="" significance="" level,="" a.="" e.="" what="" is="" the="" final="" conclusion?="" o="" a.="" there="" is="" not="" sufficient="" evidence="" to="" warrant="" rejection="" of="" the="" claim="" that="" 94%="" of="" adults="" own="" a="" cell="" phone.="" o="" b.="" there="" is="" sufficient="" evidence="" to="" warrant="" rejection="" of="" the="" claim="" that="" 94%="" of="" adults="" own="" a="" cell="" phone.="" o="" c.="" there="" is="" sufficient="" evidence="" to="" support="" the="" claim="" that="" 94%="" of="" adults="" own="" a="" cell="" phone.="" o="" d.="" there="" is="" not="" sufficient="" evidence="" to="" support="" the="" claim="" that="" 94%="" of="" adults="" own="" a="" cell="">
A poll of 2,009 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 94% of adults own cell phones. Use the normal distribution as an<br>approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).<br>Test of p 0.94 vs p 0.94<br>Sample X<br>Sample p<br>95% CI<br>Z-Value<br>P-Value<br>1<br>1912<br>2,009<br>0.951717<br>(0.942344,0.961091)<br>2.21<br>0.027<br>a. Is the test two-tailed, left-tailed, or right-tailed?<br>O Right tailed test<br>O Left-tailed test<br>O Two-tailed test<br>b. What is the test statistic?<br>The test statistic is<br>(Round to two decimal places as needed.)<br>c. What is the P-value?<br>The P-value is.<br>(Round to three decimal places as needed.)<br>d. What is the null hypothesis and what do you conclude about it?<br>Identify the null hypothesis.<br>O A. Ho: p=0.94<br>Trash<br>Click to select your answer(s).<br>

Extracted text: A poll of 2,009 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 94% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p 0.94 vs p 0.94 Sample X Sample p 95% CI Z-Value P-Value 1 1912 2,009 0.951717 (0.942344,0.961091) 2.21 0.027 a. Is the test two-tailed, left-tailed, or right-tailed? O Right tailed test O Left-tailed test O Two-tailed test b. What is the test statistic? The test statistic is (Round to two decimal places as needed.) c. What is the P-value? The P-value is. (Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. O A. Ho: p=0.94 Trash Click to select your answer(s).

Jun 02, 2022
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