Question Detail: I. Descriptive Statistics: (20 pts) Download the data set gerstman1.sav. Complete the following: 1) List the level of measurement for the variables, AGE, SEX, AGEGRP, SBP1 in the data...

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Question Detail:


I. Descriptive Statistics: (20 pts)


Download the data set gerstman1.sav. Complete the following:


1) List the level of measurement for the variables, AGE, SEX, AGEGRP, SBP1 in the data set and describe the appropriate numerical and descriptive statistics based on these. 4 pts


2) Calculate (by hand) the mean and standard deviation for age based on the first 20 records in the data set. Use the table below to do your calculations. 4 pts

































































































Record Number




AGE




Observed



Mean




Difference




Difference



Squared




1




3




2




11




3




15




4




46




5




14




6




35




7




46




8




35




9




40




10




29




11




22




12




16




13




31




14




42




15




22




16




45




17




24




18




1




19




28




20




25




Sum



3) Generate numerical and graphical descriptive statistics for each of the variables, namely, AGE, SEX, AGEGRP and SBP1. 8 pts


4) Interpret the output you generated in part 3 for each of the variables in the data set. 4 pts



II. Paired and Independentttests: (20 pts)


Download the data set HIV.sav and use SPSS to complete the following calculations. Be sure to include interpretation of the SPSS output in your responses.


1) Use the 5-step approach to hypothesis testing and the calculation of the 95% confidence intervals to answer the following research question: Did you observe a significant difference in Systolic Blood Pressure (SBP) over the course of the study? (10 pts)


2) Use the 5-step approach to hypothesis testing and the calculation of the 95% confidence intervals to answer the following research question: Is there a difference in SBP1 based on HIV status? (10 pts)



III. Cross-Tabulation: (20pts)


Download the data set alcohol_Bladder.sav and use SPSS to complete the following calculations. Be sure to include interpretation of the SPSS output in your responses.


1) Use the 5-step approach to hypothesis testing to answer the following research question: In the sample provided in alcohol_Bladder.sav, are the variables income and Bladder Cancer independent of each other? (Note:The question could also be asked: Is there an association between the variables because the lack of independence implies an association)? (10 pts)


2) Answer the following based on the cross-tabulation of alcohol consumption and Bladder Cancer: (10 pts)










































Alcohol consumption * Bladder Cancer Crosstabulation



Count



Bladder Cancer



Total



No



Yes



Alcohol consumption



"Less than 1 drink per week"



30



54



84



4 or more drinks per month



22



115



137



Total



52



169



221




  • Calculate the odds ratio. 4 pts

  • Describe how the odds ratio differs from the relative risk or risk ratio and why you would chose it here. 2 pts

  • Interpret the odds ratio and how it might impact the practice of public health practitioners. 2 pts

  • If you wanted to know whether this relationship was statistically significant what test(s) could you use? 2 pts



IV. ANOVA: 20pts


Download the data set inc-pov-hlthins.sav and use SPSS to complete the following calculations. Be sure to include interpretation of the SPSS output in your responses.


1) Produce box plots of income for each region of the US in the data set and interpret them. Based on the box plots do you expect to find a difference between any of the groups? 4 pts


2) Create descriptive statistics for each region, using the variable income. 4 pts



  • Include skewness and kurtosis in the output. 2 pts

  • Create a histogram for each group. 2 pts


3) Run the ANOVA for income based on region. Include the ANOVA table and the test for Homogeneity of Variance. Interpret the results. 6 pts


4) Conduct post hoc analysis using Bonferroni and LSD methods to control for multiple testing. 6 pts



  • Provide the output. 2 pts



  • Interpret your results. 3 pts

  • Why do you need to use methods like Bonferroni and LSD with the ANOVA? 1 pt



V. Regression: 20pts


1) Download the data set Gender_BMI.sav and use SPSS to complete the following calculations.


Use an independentttestandsimple linear regression to identify whether a relationship exists between gender and BMI. (10 pts)



  • Run the appropriatettest in SPSS, report the significance of the difference in means and the confidence interval, and interpret the results. 4 pts

  • Run the simple linear regression in SPSS, report the significance of the variable gender and the overall fit of the model (using r2). Interpret the results. 4 pts



  • How are these two approaches different? 1 pt

  • Are your conclusions the same using both tests? 1 pt


2) Answer the following questions using the provided output: 10 pts



  • Multiple Linear Regression 5 pts


Researchers looked at the Emergency Department Records of 60 adults ages 22 to 46 years who arrived in the ED complaining of chest pain during a 6 month period of time. They did not use a random sample as they wanted 30 males and 30 females in the study. They collected information on BMI (a measure of overweight/obesity), Age, SBP (Systolic Blood Pressure) and the diagnosis of Diabetes. Their first hypothesis (alternative) was that the dependent variable SBP is associated with BMI, Age, Diabetes, and Gender. They conducted a multiple linear regression to test their hypothesis. Here are the results (note that they had two models and chose to use the second one):




































Model Summaryc



Model



R



R Square



Adjusted R Square



Std. Error of the Estimate



1



.796a



.634



.608



5.443



2



.792b



.627



.607



5.445



a. Predictors: (Constant), Diabetes, Age, Gender, BMI


b. Predictors: (Constant), Age, Gender, BMI


c. Dependent Variable: SBP































































































































































ANOVAc



Model



Sum of Squares



df



Mean Square



F



1



Regression



2824.968



4



706.242



23.839



.000a



Residual



1629.408



55



29.626



Total



4454.376



59



2



Regression



2794.222



3



931.407



31.418



.000b



Residual



1660.155



56



29.646



Total



4454.376



59



a. Predictors: (Constant), Diabetes, Age, Gender, BMI


b. Predictors: (Constant), Age, Gender, BMI


c. Dependent Variable: SBP




Coefficientsa



Model



Standardized Coefficients



t



95.0% Confidence Interval for B



Beta



Lower Bound



Upper Bound



1



(Constant)



8.092



.000



57.471



95.309



Gender



-.189



-2.100



.040



-6.381



-.149



BMI



.557



6.130



.000



1.213



2.392



Age



.507



6.067



.000



.426



.847



Diabetes



-.089



-1.019



.313



-4.752



1.549



2



(Constant)



8.885



.000



55.243



87.407



Gender



-.173



-1.950



.056



-6.054



.081



BMI



.574



6.413



.000



1.276



2.436



Age



.517



6.243



.000



.441



.859



a. Dependent Variable: SBP



1) Which variables in model 1 are significant? 1 pt


2) Which variables in model 2 are significant? 1 pt


3) Why did they choose model 2? 1 pt


4) What is the “fit” of model 2 (the one they chose to use)? 1 pt


5) Is this a good model, why or why not? 1 pt



  • Multiple Logistic Regression 5 pts


The Emergency Department Researchers selected another 60 adults and again looked at Age, SBP, BMI, Gender, and Diabetes. This time however, they also collected information on whether the chest pain was diagnosed as an MI (aka Heart Attack) or something else. Now their alternative hypothesis was that gender was related to the diagnosis of an MI, after controlling for Age, SBP, BMI, and Diabetes. They used multiple logistic regression to test their hypothesis and these are their results (note that there are multiple models and they chose to use the final one):



































































































































Model Fitting Information



Model



Model Fitting Criteria



Likelihood Ratio Tests



-2 Log Likelihood



Chi-Square



df



Intercept Only



74.995



Final



16.398



58.598



5



.000




Pseudo R-Square



Cox and Snell



.623



Nagelkerke



.866



McFadden



.767




Parameter Estimates



Heart Attacka



B



Std. Error



Wald



df



Exp(B)



No



Intercept



115.037



43.679



6.936



1



.008



BMI



-1.400



.572



5.995



1



.014



.247



Age



.037



.116



.099



1



.753



1.037



Diabetes



.811



1.471



.304



1



.581



2.251



SBP



-.469



.213



4.849



1



.028



.626



[Gender=1]



-11.866



4.695



6.389



1



.011



7.025E-6



[Gender=2]



0b



.



.



0



.



.























































Parameter Estimates



Heart Attacka



95% Confidence Interval for Exp(B)



Lower Bound



Upper Bound



No



Intercept



BMI



.080



.756



Age



.826



1.303



Diabetes



.126



40.193



SBP



.412



.950



[Gender=1]



7.088E-10



.070



[Gender=2]



.



.



1) Is the final model significant? 2 pts


2) What are the odds ratios for each of the significant variables, and what do they mean? 2 pts


3) Will this model help the researchers, why or why not? 1 pt

Answered Same DayDec 21, 2021

Answer To: Question Detail: I. Descriptive Statistics: (20 pts) Download the data set gerstman1.sav. Complete...

David answered on Dec 21 2021
112 Votes
PUBH6125 FINAL EXAM
FINAL EXAM
PUBH 6125/8125 Biostatistics
Answer the following questions. Copy and paste any required data charts or summaries into this Word document. Use additional space as needed. Be sure to include your name on the document and use the file naming convention. This exam is open book and open notes.
I. Descriptive Statistics: (20 pts)
Download the data set gerstman1.sav. Complete the following:
1) List the level of measurement for the variables, AGE, SEX, AGEGRP, SBP1 in the data set and describe the appropriate numerical and descriptive statistics based on these. 4 pts
Answer: The following table shows the Name of the variables and the Measurement for these variables:
    Variable Name
    Measurement
    AGE
    Scale
    SEX
    Nominal
    AGEGRP

    Ordinal
    SBP1
    Scale
2) Calculate (by hand) the mean and standard deviation for age based on the first 20 records in the data set. Use the table below to do your calculations. 4 pts
    Record Number
    AGE
    Observed
Mean
    Difference
    Difference
Squared
    1
    3
    
    
    
    2
    11
    
    
    
    3
    15
    
    
    
    4
    46
    
    
    
    5
    14
    
    
    
    6
    35
    
    
    
    7
    46
    
    
    
    8
    35
    
    
    
    9
    40
    
    
    
    10
    29
    
    
    
    11
    22
    
    
    
    12
    16
    
    
    
    13
    31
    
    
    
    14
    42
    
    
    
    15
    22
    
    
    
    16
    45
    
    
    
    17
    24
    
    
    
    18
    1
    
    
    
    19
    28
    
    
    
    20
    25
    
    
    
    Sum
    
    
    
    
Answer:
    Record Number
    AGE
    Observed
    Difference
    Difference
    
    
    Mean
    
    Squared
    1
    3
    26.5
    -23.5
    552.25
    2
    11
    26.5
    -15.5
    240.25
    3
    15
    26.5
    -11.5
    132.25
    4
    46
    26.5
    19.5
    380.25
    5
    14
    26.5
    -12.5
    156.25
    6
    35
    26.5
    8.5
    72.25
    7
    46
    26.5
    19.5
    380.25
    8
    35
    26.5
    8.5
    72.25
    9
    40
    26.5
    13.5
    182.25
    10
    29
    26.5
    2.5
    6.25
    11
    22
    26.5
    -4.5
    20.25
    12
    16
    26.5
    -10.5
    110.25
    13
    31
    26.5
    4.5
    20.25
    14
    42
    26.5
    15.5
    240.25
    15
    22
    26.5
    -4.5
    20.25
    16
    45
    26.5
    18.5
    342.25
    17
    24
    26.5
    -2.5
    6.25
    18
    1
    26.5
    -25.5
    650.25
    19
    28
    26.5
    1.5
    2.25
    20
    25
    26.5
    -1.5
    2.25
    Sum
    530
     
     
    3589
Here the mean = 26.5 and Standard Deviation = √(3589/20) = 13.4
3) Generate numerical and graphical descriptive statistics for each of the variables, namely, AGE, SEX, AGEGRP and SBP1. 8 pts
Answer: The following table shows the descriptive statistics for AGE and SBP1:
    Descriptive Statistics
    
    Range
    Minimum
    Maximum
    Mean
    Std. Deviation
    Variance
    Skewness
    Kurtosis
    age
    63
    1
    64
    28.16
    14.674
    215.322
    .167
    -.654
    sbp1
    82
    61
    143
    109.02
    16.631
    276.579
    -.411
    -.020
The following figure shows the histogram for AGE:
The following figure shows the histogram for SBP1:
The following table shows the frequency table for SEX:
    sex
    
    Frequency
    Percent
    Valid Percent
    Cumulative Percent
    Valid
    F
    36
    48.0
    48.0
    48.0
    
    M
    39
    52.0
    52.0
    100.0
    
    Total
    75
    100.0
    100.0
    
The following figure shows the pie chart of SEX:
The following table shows the frequency table for AGEGRP:
    agegrp
    
    Frequency
    Percent
    Valid Percent
    Cumulative Percent
    Valid
    0 - 9
    16
    21.3
    21.3
    21.3
    
    10 - 19
    17
    22.7
    22.7
    44.0
    
    20 - 29
    17
    22.7
    22.7
    66.7
    
    30 - 39
    15
    20.0
    20.0
    86.7
    
    40 - 49
    8
    10.7
    10.7
    97.3
    
    50 - 59
    2
    2.7
    2.7
    100.0
    
    Total
    75
    100.0
    100.0
    
The following figure shows the pie chart of AGEGRP:
4) Interpret the output you generated in part 3 for each of the variables in the data set. 4 pts
Answer: From the above tables we can see that the mean AGE is 28.16 with standard deviation 14.674. The minimum age was 1 and the maximum was 64 with range of 63. The coefficient of skewness is 0.167 so AGE is slightly positively skewed and coefficient of kurtosis is -0.654 so AGE is platykurtic.
the mean sbp1 is 109.02 with standard deviation 16.631. The minimum sbp1 was 61 and the maximum was 143 with range of 82. The coefficient of skewness is -0.411 so sbp1 is slightly negatively skewed and coefficient of kurtosis is -0.02 so sbp1 is platykurtic.
II. Paired and Independent t tests: (20 pts)
Download the data set HIV.sav and use SPSS to complete the following calculations. Be sure to include interpretation of the SPSS output in your responses.
1) Use the 5-step approach to hypothesis testing and the calculation of the 95% confidence intervals to answer the following research question: Did you observe a significant difference in Systolic Blood Pressure (SBP) over the course of the study? (10 pts)
Answer: Here we want to test whether there is a significant difference in Systolic Blood Pressure (SBP) over the course of the study.
We assume that the systolic blood pressure before the course (sbp1) follows Normal distribution with mean m1 and the systolic blood pressure after the course (sbp1) follows Normal distribution with mean m2. Here we want to test, H: m1 = m2 vs. K: m1 ≠ m2.
Here we will use paired samples t-test. The results are given below:
     
    Paired Differences
    t
    df
    Sig. (2-tailed)
    
    Mean
    Std. Deviation
    Std. Error Mean
    95% Confidence Interval of the Difference
    
    
    
    
    
    
    
    Lower
    Upper
    
    
    
    sbp1 - sbp2
    6.878
    3.415
    .402
    6.076
    7.681
    17.088
    71
    .000
From the above table we can see that the observed value of t = 17.088. Here the p-value of the test almost zero (from ‘Sig. (2-tailed)’). Since the p-value is less than 0.05 we reject H at 5% level of significance and conclude that there is a significant difference in Systolic Blood Pressure (SBP) over the course of the study.
Here the 95% confidence interval for the difference is (6.076, 7.681).
2) Use the 5-step approach to hypothesis testing and the calculation of the 95% confidence intervals to answer the following research question: Is there a difference in SBP1 based on HIV status? (10 pts)
Answer: Here we want to test whether there is a significant difference in SBP1 based on HIV status.
We assume that SBP1 for HIV = Y follows Normal distribution with mean m1 and SBP1 for HIV = N follows Normal distribution with mean m2. Here we want to test, H: m1 = m2 vs. K: m1 ≠ m2.
Here we will use independent samples t-test. The results are given below:
     
    Levene's Test for Equality of Variances
    t-test for Equality of Means
    
    F
    Sig.
    t
    df
    Sig. (2-tailed)
    Mean Difference
    Std. Error Difference
    95% Confidence Interval of the Difference
    
    
    
    
    
    
    
    
    Lower
    Upper
    Equal variances assumed
    .109
    .743
    -2.580
    70
    .012
    -9.679
    3.752
    -17.162
    -2.197
From the above table we can see that for Levene’s Test for Equality of Variance, the observed value of F = 0.109 with p-value = 0.743. Since the p-value is greater than 0.05 so we accept the null hypothesis of equality of variance at 5% level of significance. So, here we can assume equality of variance. Now, the observed value of t = -2.58. Here the p-value of the test is 0.012 (from ‘Sig. (2-tailed)’). Since the p-value is less than 0.05 we reject H at 5% level of significance and conclude that there is a significant difference in SBP1 based on HIV status.
Here the 95% confidence interval for the difference is (-17.162, -2.197).
III. Cross-Tabulation: (20pts)
Download the data set alcohol_Bladder.sav and use SPSS to complete the following calculations. Be sure to include interpretation of the SPSS output in your responses.
1) Use the 5-step approach to hypothesis testing to answer the following research question: In the sample provided in alcohol_Bladder.sav, are the variables income and Bladder Cancer independent of each other? (Note: The...
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