Question 7 Background : Vehicle Ownership in Ann Arbor Vehicle ownership: Suppose the following probabilities reflect the number of vehicles per household owned by residents of Ann Arbor. (Note that...


Read the following prompt and graph and complete 7.a, 7.c, and 7.d


Question 7 Background :<br>Vehicle Ownership in Ann Arbor<br>Vehicle ownership: Suppose the following probabilities reflect the number of vehicles per household owned by residents of Ann Arbor. (Note that this<br>data ignores the small number of owners of four or more vehicles.)<br>X = number of vehicles/ household<br>2<br>3<br>P(X = x)<br>0.08<br>0.42<br>0.38<br>0.12<br>Question 7 Subquestions<br>7.a<br>What is the expected number of vehicles per household for residents of Ann Arbor?<br>Provide an appropriate symbol, the value (with supporting work), and units.<br>No answer entered. Click above to enter an answer.<br>

Extracted text: Question 7 Background : Vehicle Ownership in Ann Arbor Vehicle ownership: Suppose the following probabilities reflect the number of vehicles per household owned by residents of Ann Arbor. (Note that this data ignores the small number of owners of four or more vehicles.) X = number of vehicles/ household 2 3 P(X = x) 0.08 0.42 0.38 0.12 Question 7 Subquestions 7.a What is the expected number of vehicles per household for residents of Ann Arbor? Provide an appropriate symbol, the value (with supporting work), and units. No answer entered. Click above to enter an answer.
7.c<br>What is the probability that a randomly selected resident owns less than 2 vehicles?<br>P (X < 2) = 0.88<br>P (X < 2) = 0.88<br>P (X < 2) = 0.5<br>P (X < 2) = 0.50<br>7.d<br>If you knew a resident of Ann Arbor is a vehicle owner (so they own at least one vehicle), what is the probability that the resident owns exactly 2<br>vehicles?<br>P(X = 2| X 21) = 0.38<br>P(X = 2|X21) = 0.4130<br>P(X = 2| X 21) = 0.475<br>P(X = 2|X21) = 0.4565<br>P(X = 2 |X 21) = 1<br>

Extracted text: 7.c What is the probability that a randomly selected resident owns less than 2 vehicles? P (X < 2)="0.88" p="" (x="">< 2)="0.88" p="" (x="">< 2)="0.5" p="" (x="">< 2)="0.50" 7.d="" if="" you="" knew="" a="" resident="" of="" ann="" arbor="" is="" a="" vehicle="" owner="" (so="" they="" own="" at="" least="" one="" vehicle),="" what="" is="" the="" probability="" that="" the="" resident="" owns="" exactly="" 2="" vehicles?="" p(x="2|" x="" 21)="0.38" p(x="2|X21)" =="" 0.4130="" p(x="2|" x="" 21)="0.475" p(x="2|X21)" =="" 0.4565="" p(x="2" |x="" 21)="">

Jun 09, 2022
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