Question 5 of 10 uestion 5 The time usage of a certain printer cartridge follows a normal probability distribution with mean 50 hours and standard deviation of 167 minutes. What time usage guarantee...

I need the answer as soon as possibleQuestion 5 of 10<br>uestion 5<br>The time usage of a certain printer cartridge follows a normal probability distribution with mean 50 hours and standard deviation of 167 minutes. What time usage guarantee (in hours should the manufacnurer<br>advertise in order to ensure that only 0.01195 of the cartridges fail to meet the guaranteed time usage?<br>OA 0.64<br>O B. 39.62<br>OC.0.48<br>OD 6038<br>

Extracted text: Question 5 of 10 uestion 5 The time usage of a certain printer cartridge follows a normal probability distribution with mean 50 hours and standard deviation of 167 minutes. What time usage guarantee (in hours should the manufacnurer advertise in order to ensure that only 0.01195 of the cartridges fail to meet the guaranteed time usage? OA 0.64 O B. 39.62 OC.0.48 OD 6038

Jun 11, 2022
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