a=2 / b=5
25*b=125 / 60*b=300
P= 1.2*a=2.4
0.4*a=0.8 0.7*a=1.4
Extracted text: Question 2 Two wooden members of (25*b) * (60*b)-mm uniform rectangular cross section are joined by the simple glued joint shown. Knowing that P= 1.2*a kN and that the ultimate strength of the glue is 0.4*a MPa in tension and 0.7*a MPa in shear, determine the factor of safety. 25°b mm 60'b mm