QUESTION 2. ELECTION- BORDA METHOD. Let's do the exact same set of 67 preference lists, but this time we'll resolve the election using the Borda count. 15 13 12 10 9. 8. Elephant Zebra Elephant Hyena...

QUESTION 2. ELECTION- BORDA METHOD. Let's do the exact same set of 67 preference lists, but this<br>time we'll resolve the election using the Borda count.<br>15<br>13<br>12<br>10<br>9.<br>8.<br>Elephant<br>Zebra<br>Elephant<br>Hyena<br>Baboon<br>Baboon<br>Zebra<br>Baboon<br>Hyena<br>Baboon<br>Hyena<br>Elephant<br>Нyena<br>Elephant<br>Elephant<br>Zebra<br>Hyena<br>Zebra<br>Baboon<br>Zebra<br>Baboon<br>Elephant<br>Нyena<br>Zebra<br>Show the totals for the 4 candidates.<br>

Extracted text: QUESTION 2. ELECTION- BORDA METHOD. Let's do the exact same set of 67 preference lists, but this time we'll resolve the election using the Borda count. 15 13 12 10 9. 8. Elephant Zebra Elephant Hyena Baboon Baboon Zebra Baboon Hyena Baboon Hyena Elephant Нyena Elephant Elephant Zebra Hyena Zebra Baboon Zebra Baboon Elephant Нyena Zebra Show the totals for the 4 candidates.

Jun 04, 2022

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QUESTION 2. ELECTION- BORDA METHOD. Let's do the exact same set of 67 preference lists, but this time we'll resolve the election using the Borda count. 15 13 12 10 9. 8. Elephant Zebra Elephant Hyena...

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