QUESTION 1 A simple curve with tangents AV and VE have azimuth of 260°48' and 285°40' respectively. Point B is taken along AV and C along VE. The azimuth and distance of BC are 272 16' and 61.22 m...


QUESTION 1<br>A simple curve with tangents AV and VE have azimuth of 260°48' and 285°40' respectively. Point B is taken along AV and C along VE. The azimuth and distance of BC are 272 16' and<br>61.22 m respectively. The degree of curve is 5°. The stationing of point B is 8 + 126.3.<br>1. Determine the radius of the simple curve.<br>a. 184.99 m<br>b. 229.18 m<br>c. 314.67 m<br>d. 287.25 m<br>2. Determine the length of curve.<br>a. 99.47 m<br>b. 85.45 m<br>c. 51.93 m<br>d. 79.12 m<br>3. Determine the stationing of PT.<br>a. 8 + 155.21<br>b. 8 + 208.98<br>c. 8 + 311.03<br>d. 8 + 194.47<br>

Extracted text: QUESTION 1 A simple curve with tangents AV and VE have azimuth of 260°48' and 285°40' respectively. Point B is taken along AV and C along VE. The azimuth and distance of BC are 272 16' and 61.22 m respectively. The degree of curve is 5°. The stationing of point B is 8 + 126.3. 1. Determine the radius of the simple curve. a. 184.99 m b. 229.18 m c. 314.67 m d. 287.25 m 2. Determine the length of curve. a. 99.47 m b. 85.45 m c. 51.93 m d. 79.12 m 3. Determine the stationing of PT. a. 8 + 155.21 b. 8 + 208.98 c. 8 + 311.03 d. 8 + 194.47

Jun 11, 2022
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