Subject : Fluid mechanics
Note:I have some solution but didn't understand.. Make sure your solution every step and calculation clearly otherwise leave it. if you are submit again same solution I will dislike.
Extracted text: Q2: A 300mm by 460mm rectangular pipe carries oil at 105 kpa absolute and 20c through 460m with an average velocity of 2.97 m/s. determine the loss and the pressure drop, assuming the pipe is horizontal and the size of the surface imperfections is 0.00055m.
Extracted text: Sor bancy Lauw head 1oss = LV? 4*R*ag The lost head term must be revised 8liqhtly to apply to nonciocculcom eross sechions The resceeting equation coiu apply to tun balen fioo coills neasonablo he dliameter (5e hydnacdic nadius. accLUTIRCy Substitule for Ceccurnaey. R= A P > R= d = d= R4 h= 4 4XRメ39 R= 0:300x 0:460 2*0 300+ 0.460 > for 15e 300 mmx460 Mm R=D 0.0908 m 5. 75263.42 Re=4VR -> 4*2.97*0.0908. 101 (49 x10 105 for E From Diagmam A-1, f- 0.084 4R 0.00055 4*0.0908 = 0.0015. 1D Head 1oss = O.024*460 Q.97) 4*0.0908xQx9.51 - 13.665 m of cair pressurne drop = Yh = (L05)* |18 * 13.665 = 167.63 Pa 101