Q.1.1 A cable of uniform cross-sectional area is stretched between two supports 80 m apart with one end 5 m above the other (as in figure below). The cable is loaded with uniformly distributed load of...

answer quicklyQ.1.1 A cable of uniform cross-sectional area is stretched between two supports 80 m apart with one end 5 m<br>above the other (as in figure below). The cable is loaded with uniformly distributed load of 7 kN/m and the sag of<br>the cable measured from the higher end is 6 m. Calculate horizontal tension in the cable maximum<br>tension in the cable.<br>7 kNm<br>80 m<br>d = 5 m<br>

Extracted text: Q.1.1 A cable of uniform cross-sectional area is stretched between two supports 80 m apart with one end 5 m above the other (as in figure below). The cable is loaded with uniformly distributed load of 7 kN/m and the sag of the cable measured from the higher end is 6 m. Calculate horizontal tension in the cable maximum tension in the cable. 7 kNm 80 m d = 5 m

Jun 11, 2022
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