Q1 What is the area of the rectangular parcel with the dimension of (3280.9 ft × 6561.8 ft) using the following units? The area in km^2. 1)3 2)2 3)1.5 4)2.5 The area in hectare. 1)300 2)200 3)250 4)150 The area in yard^2. 1)2392000 2)2485000 3)2678000 4)2259000 The area in acre. 1)475.32 2)467.54 3)492.21 4)505.68 Q2 Compute the length in the foot, corresponding to the following distance measured with Gunter’s chain of 14 ch 66 lk. The length value in ft. 1)976.86 ft 2)967.56 ft. 3)934.44 ft. 4)958.92 ft. The length value in m. 1)297.73 m 2)289.64 m 3)305.65 m Q3 Select the suitable choice. 1) The value of the equivalent area of 84 ft^3 is ......... liters. 1)2189.5 2)2378.6 3)2455.7 4)2665.8 2) The equivalent value for the angle of 154.325˚ is ........... gradian. 1)169.835 2)171.472 3)176.925 4)178.665 3) The value of the equivalent volume of 36 m^3 is ............ gallons. 1)7428 2)7550 3)7889 4)7920 4) The value of the equivalent area of 39850 acres is .............. miles^2. 1)61.95 2)62.27 3)63.45 4)65.63 5) The value of the equivalent area of 2.5 hectares is .......... yards^2. 1)29250 2)29900 3)30100 4)30500 4)291.23 m Q4 -A. For the angle value of 23˚44' 36'' in degree (14 grades) . The angle value in radian equal to ....... . 1)0.4144 rad 2)0.4022 rad 3)0.4232 rad The angle value in gradian equal to ....... . 1)24.2816 gradian 2)26.3814 gradian 3)25.3452 gradian Q4 b For the radian angle of 0.91 rad (10 grades). The equivalent value of angle in (degree, minute, second). 1)53 ˚ 18 ' 24.46 '' 2)52 ˚ 08 ' 21.12 '' 3)54 ˚ 10 ' 36.28 '' 4)56 ˚ 16 ' 31.22 '' A steel tape standardized of (l = 30 m) at 20°C and supported throughout under a tension of (P = 6.0 kg) was found to be (l' = 30.016 m) long. The tape had a cross-sectional area of (A = 0.060 cm2) and a weight of (W = 0.04 kg/m). This tape was held horizontal, supported at the ends only, with a constant tension of (P1 = 10.0 kg), to measure a line from A to B in three segments. The data listed in the following Table were recorded. E is 2,000,000 kg/cm2 and K= 0.0000116. Apply corrections to determine the correct length of the line for the following: (a) The tape length correction is equal to ..... . 1)+ 0.04619 m 2)+ 0.04882 m 3)+ 0.043223 m 4)+ 0.05012 m (b) Temperature corrections is equal to ..... , 1)- 0.004983 m. 2)- 0.005021 m. 3)- 0.003132 m 4)- 0.003243 m (c) The pull correction is equal to ..... . 1)+ 0.002887 m 2)+ 0.003988 m 3)+ 0.001976 m 4)+ 0.002244 m (d) The sag corrections are equal to ..... . 1)- 0.036 m 2)- 0.0125 m 3)- 0.0485 m 4)- 0.0462 m (e) The Final correction of distance AB for all corrections equal to ...... . 1)86.59559 m 2)86.64409 m 3)86.69259 m 4)86.58998 m