Consider the common source amplifier shown in the figure below. Assume that the transistorhas been biased in the saturation region. It has an ID = 1 mA, additionally k = 617 × 10−6 A/V2and Cgs = 1 pF....


Consider the common source amplifier shown in the figure below. Assume that the transistor
has been biased in the saturation region. It has an ID = 1 mA, additionally k = 617 × 10−6 A/V2
and Cgs = 1 pF. You may ignore channel length modulation and all other parasitic capacitors.
Sketch the Bode plots for this amplifier.


pVDD<br>9 k<br>OVOUT<br>1 k<br>1 k2<br>VIN<br>100 pF<br>I<br>

Extracted text: pVDD 9 k OVOUT 1 k 1 k2 VIN 100 pF I

Jun 10, 2022
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