Prove this statement: we have numbers {a1, a2, a3. .,a2n} which are even and positive, but 0

Prove this statement:<br>we have numbers {a1, a2, a3. .,a2n} which<br>are even and positive, but 0 < {a1, a2,<br>a3.,a2n} < 1 (example:0.2, 0.4, 0.002,<br>0.00000008)<br>and the sum of these numbers are 1.<br>Now prove there always have the product of<br>two neighbor numbers am * am+1 is less or<br>equal to 1/n2<br>

Extracted text: Prove this statement: we have numbers {a1, a2, a3. .,a2n} which are even and positive, but 0 < {a1,="" a2,="" a3.,a2n}="">< 1="" (example:0.2,="" 0.4,="" 0.002,="" 0.00000008)="" and="" the="" sum="" of="" these="" numbers="" are="" 1.="" now="" prove="" there="" always="" have="" the="" product="" of="" two="" neighbor="" numbers="" am="" *="" am+1="" is="" less="" or="" equal="" to="">

Jun 04, 2022

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Prove this statement: we have numbers {a1, a2, a3. .,a2n} which are even and positive, but 0

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