Prove that P( ) and Q( ) are both different from O( )—that is, we can’t just use either of the new definitions without changing what we meant. Specifically, prove that there exist functions f and g such that .
1. . . either (i) f = O(g) but f 6= P(g), or (ii) f 6= O(g) but f = P(g).
2 . . . either (i) f = O(g) but f 6= Q(g), or (ii) f 6= O(g) but f = Q(g).
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