Prove (5.7).
Hint: Step (a). Let A be the event that X1, X2 ∈ [h/2, 3h/2], X3,...,Xn ∈ [5h/2, 1], and Y1 = Y2. Then P{A} > 0 and
E (mn(x)−m(x))2 µ(dx) = E mn(x) 2 dx ≥ E
Step (b). Given A, on [h/2, 3h/2], the locally linear kernel estimate mn has the form
mn(x) = ±2 ∆ (x − c),
where ∆ = |X1 − X2| and h/2 ≤ c ≤ 3h/2. Then
E
Step (c).
E 1 ∆|A = E 1 ∆ = ∞.
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