Prove (15.6). Hint: Apply the identity g(1) = l j=0 g(j) (0) j! (1 − 0)j + 1 l! 1 0 (1 − t) l g(l+1)(t) dt to g(t) = f(x + t (u − x), z + t (v − z)).


Prove (15.6). Hint: Apply the identity



g(1) = l j=0 g(j) (0) j! (1 − 0)j + 1 l!




1 0 (1 − t) l g(l+1)(t) dt


to



g(t) = f(x + t (u − x), z + t (v − z)).



May 03, 2022
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