Proposition 6.1.19. An integer is divisible by 3 if and only if the sum of its digits is divisible by 3. Proposition 6.1.21. A number is divisible by 11 if and only if the alternat- ing sums of the...


Please do Exercise 6.1.22 part abc and please show step by step


Proposition 6.1.19. An integer is divisible by 3 if and only if the sum of<br>its digits is divisible by 3.<br>Proposition 6.1.21. A number is divisible by 11 if and only if the alternat-<br>ing sums of the digits is divisible by 11. (Note: alternating sums is where<br>the signs of the number alternate when summing.)<br>PROOF. Given an integer with digits do ... dn where the number is writeen<br>as dndn-1...dıdo we can write<br>n = dm · 10

Extracted text: Proposition 6.1.19. An integer is divisible by 3 if and only if the sum of its digits is divisible by 3. Proposition 6.1.21. A number is divisible by 11 if and only if the alternat- ing sums of the digits is divisible by 11. (Note: alternating sums is where the signs of the number alternate when summing.) PROOF. Given an integer with digits do ... dn where the number is writeen as dndn-1...dıdo we can write n = dm · 10" + dm-1 · 10m-1 + ...+ do · 10º it follows that: mod (n, 11) = mod (dm · 10" + dm-1· 10m–1 +...+ do · 10°, 11) = mod(dm · (-1)™ + dm-1 · (–1)m-1+. = mod ((-1)" (dm – dm-1+ ·+do · 1), 11) [substitution] ..+ do · (–1)º, 11) [mod(10,11) = -1] [factor out (-1)"] ... Therefore, mod (n, 11)=0 if and only if the alternating sums of the digits of the number d, ... do is divisible by 11.
Exercise 6.1.22.<br>(a) In Proposition 6.1.19 we showed that a number is divisible by 3 if and<br>only if the sum of its digits is divisible by 3. Write a similar argument<br>and state a proposition for a number that is divisible by 9.<br>(b) Figure 6.1.1 shows a table giving the different powers of 10 mod base<br>37.<br>Based on the results shown in Figure 6.1.1, propose a divisibility rule<br>to check whether numbers are divisible by 37. Apply your rule to the<br>following numbers: 17094, 411108, 365412<br>1 base<br>37<br>2<br>3 10*n(n>o Mod(An, 37)<br>1<br>10<br>10<br>6.<br>100<br>26<br>7<br>1000<br>1<br>10000<br>10<br>100000<br>26<br>10<br>1000000<br>1<br>11 10000000<br>12 100000000<br>10<br>26<br>13<br>Figure 6.1.1. Spreadsheet to compute the powers of 10 mod 37<br>(c) Create a spreadsheet similar to the the spreadsheet in Figure 6.1.1. Use<br>your spreadsheet to find mod(10

Extracted text: Exercise 6.1.22. (a) In Proposition 6.1.19 we showed that a number is divisible by 3 if and only if the sum of its digits is divisible by 3. Write a similar argument and state a proposition for a number that is divisible by 9. (b) Figure 6.1.1 shows a table giving the different powers of 10 mod base 37. Based on the results shown in Figure 6.1.1, propose a divisibility rule to check whether numbers are divisible by 37. Apply your rule to the following numbers: 17094, 411108, 365412 1 base 37 2 3 10*n(n>o Mod(An, 37) 1 10 10 6. 100 26 7 1000 1 10000 10 100000 26 10 1000000 1 11 10000000 12 100000000 10 26 13 Figure 6.1.1. Spreadsheet to compute the powers of 10 mod 37 (c) Create a spreadsheet similar to the the spreadsheet in Figure 6.1.1. Use your spreadsheet to find mod(10", 111) for 0 <>< 8. come up with a proposition for numbers in base 111 and prove it similarly the divisibility rule for numbers in base 11 was proved in proposition 6.1.21. 8.="" come="" up="" with="" a="" proposition="" for="" numbers="" in="" base="" 111="" and="" prove="" it="" similarly="" the="" divisibility="" rule="" for="" numbers="" in="" base="" 11="" was="" proved="" in="" proposition="">
Jun 04, 2022
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