resolve problem: Redo problem (5.3) but with sand instead of clay as shown in the figure below.
(Ans.: Si(Total) = 5.75 mm)
"please resolve the problem 5.3 but sand instead of clay"
"solve all problem"
Extracted text: Problem (5.3): (Total immediate settlement) Determine the total immediate settlement of the rectangular footing shown in figure below after 2 months. 1200 kN G.S. 1.0m 3m x 4m 9 = 8000KN/m²y = 20.kN/m³ 0.6 2.0m Clay 0.5B -1.5m 0.633 Izavg) 3.0m Sand E = 20000KN/m? 4.5m 0.133 Rock 2B - 6m 2B – 0.6 Iz Solution: Since the soil profile is made up of two different soils, then the total immediate settlement will be: Si(Total) = Sa(clay) + S;(sand) Immediate Settlement of clay by Bjerrum's method: q.B Si(average )flexible =HoH1 -(5.7) From Fig.(5.4): for Dę/B = 1/3 = 0.33 and L/B = 4/3 = 1.33; Ho=0.93 for H/B = 2/3 = 0.66 and L/B = 1.33; H1=0.38 (1200/3x4)(3)(1000), S(average)flexible = (0.93)(0.38)- Immediate Settlement of sand by Schmertmann's method: 6.6 mm (2x8x1000) For square foundation: C;C2 I,Az S; = 2.5 (5.6a) C = 1-0.50 20.5 Ap At foundation level: 1200 P = D5.y = 1(20) = 20 kN/m², AP = P/A - P% = On sand surface: 20 = 80 kN/m Зx4 (80)(3)(4) P% = D5.y = 3(20) = 60 kN/m², = 32 kN/m² (2:1 method) ΔΡ (3 + 2)(4 + 2) 60 C = 1-0.5 = 0.06 <0.5 32="" ..="" use="" c="0.5" 2/12="" c2="1+0.2log" 10="" -="1+" 0.2="" log10="" 0.1="1.04" 0.1="" 0.533="" +="" 0.133="" iz="" az="" _="" (0.333)(3)="4.9.x.10-5" iz(avg.)="0.333," 2="" e="" 20000="" si(sand)="(0.5)(1.04)(32)(4.9.x.10-³)" =0.815="" mm="" *="" si(total)="6.6" +="" 0.815="7.415">
Extracted text: 1200 kN G.S. 1.0m Зт x 4m 2.0m 9c = 8000 .kN / m²,..y = 20.kN / m` sand 3.0m clay E= 20000...kN/m? Rock