Problem 3: Consider the set of polynomials {-1+3t – 21², 4 – 10t + 3t², 4 – 8t – 21²} . Let p¡(t) = – 1 + 3t – 21², p2(t) = 4 – 10t + 3ť², and p3(t) = 4 – 8t – 21². Let H = span {p,(t), P2(t), P3(t)},...


Problem 3: Consider the set of polynomials {-1+3t – 21², 4 – 10t + 3t², 4 – 8t – 21²} .<br>Let p¡(t) = – 1 + 3t – 21², p2(t) = 4 – 10t + 3ť², and p3(t) = 4 – 8t – 21². Let<br>H = span {p,(t), P2(t), P3(t)}, which is a subset of P,.<br>

Extracted text: Problem 3: Consider the set of polynomials {-1+3t – 21², 4 – 10t + 3t², 4 – 8t – 21²} . Let p¡(t) = – 1 + 3t – 21², p2(t) = 4 – 10t + 3ť², and p3(t) = 4 – 8t – 21². Let H = span {p,(t), P2(t), P3(t)}, which is a subset of P,.
Is the set of polynomials {-1+ 3t – 21², 4 – 10t + 31², 4 – 8t – 212} independent?<br>Answer this question directly without using a coordinate map.<br>[Hint: Can<br>you<br>find scalars a,b, and c, not all zero, such that<br>a (-1+3t – 2t²) +b (4 – 101 + 3t²) + c (4 – 8t – 2r²) = 0 + 0t + Or². Collecting<br>terms will again lead you to 3x3 linear system. Fell free to reuse some work from part (a)<br>to save time!]<br>If the answer is no (hint, it is), find a dependence relation for the polynomials. (Check<br>your answer).<br>Give a basis for the subspace H of P, where<br>21<br>H = span {-1+ 3t – 2t2, 4 – 10t + 3t?, 4 – 8t – 212}<br>

Extracted text: Is the set of polynomials {-1+ 3t – 21², 4 – 10t + 31², 4 – 8t – 212} independent? Answer this question directly without using a coordinate map. [Hint: Can you find scalars a,b, and c, not all zero, such that a (-1+3t – 2t²) +b (4 – 101 + 3t²) + c (4 – 8t – 2r²) = 0 + 0t + Or². Collecting terms will again lead you to 3x3 linear system. Fell free to reuse some work from part (a) to save time!] If the answer is no (hint, it is), find a dependence relation for the polynomials. (Check your answer). Give a basis for the subspace H of P, where 21 H = span {-1+ 3t – 2t2, 4 – 10t + 3t?, 4 – 8t – 212}

Jun 05, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here